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如何从API解码json响应

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我从这样的API调用数据：

$curl = curl_init();
//adding fields to the curl object to enter the site
curl_setopt($curl, CURLOPT_URL, $my_url);
curl_setopt($curl, CURLOPT_HTTPHEADER, $headers);  
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, 0);

//executing the curl call and getting data back
$jsonStr = curl_exec($curl);

curl_close($curl); // close the connection

print_r($jsonStr);

它工作正常，但问题是我无法解码json响应 . 我得到这样的东西：

[{"id":1,"name":"Books","description":null,"reference":null,"status":"active","category":{"id":"5048","name":"Ventas"},"price":[{"idPriceList":"1","name":"General","type":"amount","price":"200.0000"}],"tax":[]},{"id":2,"name":"pencil","description":null,"reference":null,"status":"active","category":{"id":"5048","name":"Ventas"},"price":[{"idPriceList":"1","name":"General","type":"amount","price":"5000.0000"}],"tax":[]}]

我试图解码并调用像“echo $ code [0] ['name']这样的值;”我不能，它显示相同的json数组，然后我试图将json数组保存为变量，如：

$json = '[{"id":1,"name":"Books","description":null,"reference":null,"status":"active","category":{"id":"5048","name":"Ventas"},"price":[{"idPriceList":"1","name":"General","type":"amount","price":"200.0000"}],"tax":[]},{"id":2,"name":"pencil","description":null,"reference":null,"status":"active","category":{"id":"5048","name":"Ventas"},"price":[{"idPriceList":"1","name":"General","type":"amount","price":"5000.0000"}],"tax":[]}]';

并试图解码它，它的工作原理，我认为问题是单引号 . 我不确定，但这是我假设基于我得到的结果 . 我是curl，json和php的新手，所以如果有人可以帮助我 .

顺便说一句，我试图像这样解码：

$code = json_decode($jsonStr ,true);
echo $code[0]['id'];

但它不起作用，它返回相同的完整json数组，而不是我想要的值

当我试图回应$ jsonStr我得到：

[{"id":1,"name":"Books","description":null,"reference":null,"status":"active","category":{"id":"5048","name":"Ventas"},"price":[{"idPriceList":"1","name":"General","type":"amount","price":"200.0000"}],"tax":[]},{"id":2,"name":"pencil","description":null,"reference":null,"status":"active","category":{"id":"5048","name":"Ventas"},"price":[{"idPriceList":"1","name":"General","type":"amount","price":"5000.0000"}],"tax":[]}]
php arrays json curl

3 回答

  • 0

    您可以使用json_decode（）方法

    请参考此链接http://php.net/manual/en/function.json-decode.php

    回复于
  • 0

    使用 json_decode() . 如果您想查看php对象以便更好地了解如何使用它，请尝试

    echo '<pre>';
echo print_r(json_decode($jsonStr, true));
echo '</pre>';
    回复于
  • 0

    不知道为什么不适合你 . 当json字符串在代码中时它确实有效 .

    <?php

$json = '[{"id":1,"name":"Books","description":null,"reference":null,"status":"active","category":{"id":"5048","name":"Ventas"},"price":[{"idPriceList":"1","name":"General","type":"amount","price":"200.0000"}],"tax":[]},{"id":2,"name":"pencil","description":null,"reference":null,"status":"active","category":{"id":"5048","name":"Ventas"},"price":[{"idPriceList":"1","name":"General","type":"amount","price":"5000.0000"}],"tax":[]}]';

$arr = json_decode($json, true);

$id = $arr[0]['id'];
$name = $arr[0]['name'];
print("$id $name\n");

    输出继电器：

    1 Books

    顺便说一下我的版本

    PHP 5.6.30 (cli) (built: Aug  8 2017 12:20:45)
    回复于

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