我有一个简单的fileUpload rest API,它将上传的文件存储在数据库中,并返回数据库中上传文件的unuque引用(uuid) .
我使用swagger来生成API文档,它就像一个魅力,但我找不到添加描述文本来描述响应内容的方法 .
这是我的REST的签名:
@POST
@Path("/upload")
@Consumes(ExtendedMediaType.MULTIPART_FORM_DATA)
@ApiOperation(
value = "Save an image",
notes = "Save the uploaded image to database.",
response = String.class)
@ApiResponses(value = {
@ApiResponse(code = 200, message = "The uploaded image has been saved.", response = String.class),
@ApiResponse(code = 500, message = "Error while trying to resize the image.<p>Internal error code: 2103", response = a.b.ErrorInfo.class)})
@Override
public String uploadImage(
@ApiParam(value = "file to upload", required = true) @FormDataParam("file") final InputStream inputStream,
@ApiParam(value = "details of the uploaded file", required = true) @FormDataParam("file") final FormDataContentDisposition fileDetail) {
//return UUID.randomUUID().toString();
}
我想将以下信息添加到API文档中,以便描述响应字符串的内容:
"The unique id of the uploaded image."
我已经检查了ApiResponses文档,但我没有找到与此主题相关的任何内容 .
我可以把这个信息放在 ApiResponse
HTTP 200旁边,但我不确定这个解决方案是否正确 .
1 回答
根据我的招摇经验,我认为必须在ApiOperation的注释字段中指定,如下所示