如何在GNU Makefile中创建非依赖的虚假目标?
要求:
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检查特定设置的规则 - 可能比下面的示例更复杂 .
-
如果此规则失败,则构建特定目标应该失败 .
-
如果此规则成功,则只有在修改其来源时才应构建特定目标 .
-
规则不能是全局规则,因为甚至不应对非特定目标执行该规则
如果在每个特定目标的编译规则之前插入规则,则可以实现这一点 . 由于它们可能是许多特定目标,我更喜欢为此规则创建虚假目标,并将此虚假目标指定为所有这些特定目标的依赖项 . 这会产生不必要的副作用,当虚假目标成功时,即使未修改其来源,也会重建这些特定目标 .
换句话说,如果其源是最新的,如何指定虚假目标以强制重建依赖目标 .
$ make --version | grep Make
GNU Make 3.82
$ make -f try.mk clean setup
rm -f try.out?
touch try.c #Dummy create source
$ make -f try.mk
touch try.out1 #Dummy compile
touch try.out2 #Dummy compile
touch try.out3 #Dummy compile
$ make -f try.mk
touch try.out3 #Dummy compile
try.out3应该 NOT 已经编译在上面/最后一个make中 .
$ cat try.mk
#try.mk
base=try
all: $(base).out1 $(base).out2 $(base).out3 #...
clean:
rm -f $(base).out?
setup:
touch $(base).c #Dummy create source
.PHONY: all clean platform_ok
#------------------------------------------------------------
#Specific targets
#------------------------------------------------------------
#Attempt 1: works, but platform check is a rule, and hence needs to be inserted wherever it is needed.
$(base).out1: $(base.c)
@if [ $(shell uname -i) == x86_64 ]; then exit 0; else exit 1; fi
touch $(base).out1 #Dummy compile
#Attempt 2: works, but platform check is global, which gets executed even when building Non-OS specific targets
$(eval platform_check:=$(shell (if [ $(shell uname -i) == x86_64 ]; then echo 0; else echo 1; fi)))
$(base).out2: $(base).c
@exit $(platform_check)
touch $(base).out2 #Dummy compile
#Attempt 3: works partially when platform check is a phony target, but target gets rebuilt even if source is uptodate.
$(base).out3: $(base).c platform_ok
touch $(base).out3 #Dummy compile
platform_ok:
@if [ $(shell uname -i) == x86_64 ]; then exit 0; else exit 1; fi
#------------------------------------------------------------
#Non-Specific targets
#------------------------------------------------------------
#...
2 回答
我会对此略有不同:
我会松散
platform_ok
:只需使用虚假目标作为仅限订单的先决条件 . 如果在依赖关系图中找到,则Make将始终执行此规则,但只有在正常先决条件更新的情况下才会执行依赖于它的目标: