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指向结构的指针作为JNA中的参数

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第三方DLL有一个函数,它期望指向结构的指针作为参数:

__declspec(dllimport) int __stdcall
SegmentImages( unsigned char* imageData, int imageWidth, int imageHeight,
               int* numOfFinger, SlapInfo** slapInfo, const char* outFilename );

它将numOfFinger指纹(通常为4)的图像分割成单个指纹(outFilename number of finger) .

SlapInfo的定义是:

struct SlapInfo {
    int fingerType; 
    Point fingerPosition[4];
    int imageQuality;
    int rotation;
    int reserved[3];
};

struct Point {
    int x;
    int y;
};

C中示例的片段:

unsigned char* imageData;
int imageWidth, imageHeight;
//obtain imageData, imageWidth and imageHeight from scanner...
int numOfFinger;
SlapInfo* slapInfo;

int result = SegmentImages( imageData, imageWidth, imageHeight, &numOfFinger,
                            &slapInfo, FINGER_IMG_PATH);

JNA

根据JNA FAQ,在我的情况下我应该使用"Structure.ByReference[]":

void myfunc(simplestruct** data_array, int count); // use Structure.ByReference[]

所以,我在Java / JNA中映射如下:

结构

public class Point extends Structure {
    public int x;
    public int y;

    public Point(){
        super();
    }

    @Override
    protected List<String> getFieldOrder() {
        return Arrays.asList("x", "y");
    }
}


public class SlapInfo extends Structure {    
    public int fingerType;
    public Point[] fingerPosition = new Point[4];
    public int imageQuality;
    public int rotation;
    public int[] reserved = new int[3];

    public SlapInfo() {
        super();
    }

    public SlapInfo(Pointer pointer){
        super(pointer);
    }

    @Override
    protected List<String> getFieldOrder() {
        return Arrays.asList("fingerType", "fingerPosition", "imageQuality",
                "rotation", "reserved");
    }

    public static class ByReference extends SlapInfo implements Structure.ByReference { }
}

功能

int SegmentImages(byte[] imageData, int imageWidth, int imageHeight, 
                  IntByReference numOfFinger, SlapInfo.ByReference[] slapInfo,
                  String outFileName);

用法

//imageData, width and height are with valid values
IntByReference nrOfFingers = new IntByReference();
SlapInfo.ByReference[] slapInfoArray = (SlapInfo.ByReference[]) 
                new SlapInfo.ByReference().toArray(4);
                //Usually, there are 4 fingers in a slap, but the correct
                //value should be the returned in nrOfFingers

int result = lib.SegmentImages(imageData, width, height,
                nrOfFingers, slapInfoArray, FINGER_IMG_PATH);

但是使用这种方法,我得到错误:

java.lang.Error: Invalid memory access
        at com.sun.jna.Native.invokeInt(Native Method)
        at com.sun.jna.Function.invoke(Function.java:419)
        at com.sun.jna.Function.invoke(Function.java:354)
        at com.sun.jna.Library$Handler.invoke(Library.java:244)
        at com.sun.proxy.$Proxy0.SegmentImages(Unknown Source)
        at scanners.JNAScanner.segmentToFile(JNAScanner.java:366)

我也尝试过:

在所有情况下,我收到错误“无效的内存访问” .

我究竟做错了什么?

1 回答

  • 1

    如果 SegmentImagesslapInfo 中返回一个或多个结构的地址,则需要使用 PointerByReference . 实际的本机类型是 struct ** ,但是您在 slapInfo 中返回的值是指针 .

    IntegerByReference iref = new IntegerByReference();
    PointerByReference pref = new PointerByReference();
    int result = SegmentImages(..., iref, pref, ...);
    

    如果在单个块中返回结构,则可以执行以下操作:

    SlapInfo s = new SlapInfo(pref.getValue());
    SlapInfo[] slaps = s.toArray(iref.getValue());
    

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