如何在webview网址上打开新屏幕点击？-Java 学习之路

-1

在我的应用程序中，我使用webview来显示一些网络数据，我想实现一种功能，如果用户点击任何链接，将打开一个新的屏幕（活动），并且url的数据将显示在该活动的webview中 . 我已经尝试将webview客户端设置为webview并覆盖其onPageStarted，shouldOverrideUrlLoading方法，但它们都在同一屏幕中打开url .

这是我的代码

webview.loadData(html, "text/html; charset=utf-8", "UTF-8");
    webview.setWebViewClient(webViewClient);
}
WebViewClient webViewClient = new WebViewClient() {
    @Override
    public void onPageStarted(WebView view, String url, Bitmap favicon) {
        if (url.startsWith("http://")) {
            Intent intent = new Intent(FirstActivity.this, WebActivity.class);
            intent.putExtra("url", url);
            startActivity(intent);
        }
    }
    @Override
    public void onPageFinished(WebView view, String url) {
    }

    @SuppressWarnings("deprecation")
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
         return false;
    }

    @TargetApi(Build.VERSION_CODES.N)
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) {

        return false;
    }

    @Override
    public void onLoadResource(WebView view, String url) {
        super.onLoadResource(view, url);
    }
};

如何实现？任何帮助将不胜感激

3 回答

试试这个：

@SuppressWarnings("deprecation")
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
    if (url.startsWith("http://")) {
        Intent intent = new Intent(FirstActivity.this, WebActivity.class);
        intent.putExtra("url", url);
        startActivity(intent);
        return true;
    }
    return false;
}

@TargetApi(Build.VERSION_CODES.N)
@Override
public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) {

    String url = request.getUrl().toString();
    if (url.startsWith("http://")) {
        Intent intent = new Intent(FirstActivity.this, WebActivity.class);
        intent.putExtra("url", url);
        startActivity(intent);
        return true;
    }
    return false;
}

回复于 2024-05-06T18:34:39+08:00

试试这个 . 但您首先需要设置一个像google.com这样的初创网站

import android.app.Activity;
import android.content.Intent;
import android.net.Uri;
import android.os.Bundle;
import android.view.KeyEvent;
import android.webkit.WebChromeClient;
import android.webkit.WebView;
import android.webkit.WebViewClient;


public class MainActivity extends Activity {

private WebView view;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    view = (WebView) this.findViewById(R.id.webView);
    view.getSettings().setJavaScriptEnabled(true);
    view.getSettings().setDomStorageEnabled(true);
    view.setWebViewClient(new MyBrowser());
    view.loadUrl("[YOUR_WEBSITE]"); //try js alert
    view.setWebChromeClient(new WebChromeClient()); // adding js alert support

}
private class MyBrowser extends WebViewClient {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if (url.startsWith("tel:") || url.startsWith("sms:") || url.startsWith("smsto:") || url.startsWith("mailto:") || url.startsWith("mms:") || url.startsWith("mmsto:") || url.startsWith("market:")) {
            Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
            startActivity(intent);
            return true;
        }
        else {
            view.loadUrl(url);
            return true;
        }
    }
}

public boolean onKeyDown(int keyCode, KeyEvent event) {
    if ((keyCode == KeyEvent.KEYCODE_BACK) && view.canGoBack()) {
        view.goBack(); //method goback()
        return true;
    }

    return super.onKeyDown(keyCode, event);
    }
}

回复于 2024-05-06T18:34:39+08:00

如果链接在网站外部，您可以执行以下操作：

webview.setWebViewClient(new LinkExtWebViewClient());

然后：

public class LinkExtWebViewClient extends WebViewClient {

    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {

        if(Uri.parse(url).getHost().endsWith(" if your site is www.myurl.com, here you have to insert 'myurl.com' ")) {
            return false;
        }
        Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
        view.getContext().startActivity(intent);
        return true;
    }
}

让我知道它是否有效:)

回复于 2024-05-06T18:34:39+08:00

如何在webview网址上打开新屏幕点击？

3 回答

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