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如何在javascript中上传多个用户的图片

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这是我的屏幕截图，看到user1上传了一些文件/图像（例如image1，image2和image3） . 另一个用户（user2）上传了一些文件/图像（image4，image5，image6） . 用户同时上传文件/图像我正在使用单个目录为用户文件上传目录 . 现在我正面临用户上传了哪些文件/图像？这个angular.js文件

'use strict';
    $(function(){
        $(document).on('click','#drop_div',function(){
            $('#file_upload').click();
        });
    });
    angular.module('app', ['angularFileUpload']).controller('AppController', ['$scope', 'FileUploader', function($scope, FileUploader) {
       var uploader = $scope.uploader = new FileUploader({url: 'upload.php'});
       console.log('uploader---------'+uploader);
        uploader.filters.push({
            name: 'customFilter',
            fn: function(item /*{File|FileLikeObject}*/, options) {
                    var type = '|' + item.type.slice(item.type.lastIndexOf('/') + 1) + '|';
                    var file_exten_val = '|pdf|jpg|jpeg|png|bmp|gif|application|x-zip-compressed|'.indexOf(type);
                    var file_name = item.name;
                    var slice_exten = file_name.split('.');
                    console.log([type,file_exten_val]);
                    if((file_exten_val == -1) && (slice_exten[1] =='epub') || (type =='x-zip-compressed')){
                        return this.queue.length < 20;
                    }else if(file_exten_val >= 0){
                        return this.queue.length < 20;
                    }          
           }
        });
    }]);

upload.php

<?php 
    if ( !empty( $_FILES ) ) {

        $tempPath = $_FILES['file']['tmp_name'];
        $uploadPath = dirname( __FILE__ ) . DIRECTORY_SEPARATOR . 'uploads' . DIRECTORY_SEPARATOR . $_FILES[ 'file' ][ 'name' ];
        echo $uploadPath;
        move_uploaded_file( $tempPath, $uploadPath );

        $answer = array( 'answer' => 'File transfer completed' );
        $json = json_encode( $answer );

        echo $json;

    } else {

        echo 'No files';

    }
    ?>
javascript php angularjs

1 回答

  • 0

    根据documentation，您可以使用您的文件发送一些表单数据（param formData ）：

    'use strict';
    $(function(){
        $(document).on('click','#drop_div',function(){
            $('#file_upload').click();
        });
    });
    angular.module('app', ['angularFileUpload']).controller('AppController', ['$scope', 'FileUploader', function($scope, FileUploader) {
       var uploader = $scope.uploader = new FileUploader({url: 'upload.php', formData: [{username: 'MyUsername'}]});
       //[...]
    }
    回复于

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