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如何使用谷歌方向API优化路线

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我正在使用谷歌方向api来解决旅行商问题 .

显然，api采用一个名为 optimize:true 的参数，然后返回 "waypoint_order": [ 1, 0, 2, 3 ] ，告诉您优化路线的最佳航路点顺序 .

事实上，当你尝试优化路线时，API就不起作用了，你得到NO_RESULTS .

例如，使用此URL可以查看添加 optimize:true| 位时API是如何失败的 .

不工作（NO_RESULTS错误）：

https://maps.googleapis.com/maps/api/directions/json?origin=place_id:ChIJdd4hrwug2EcRmSrV3Vo6llI&destination=place_id:ChIJh1a5WhEMa0gRY1JU4PEam8Q&waypoints=optimize:true|place_id:ChIJPeqVDlONbEgRk4X1zrUsKDs|place_id:ChIJ_WegsaCYc0gRlCypaxXgLjs|&key=YOUR_KEY

工作（但没有优化）：

不优化网址：https://maps.googleapis.com/maps/api/directions/json?origin=place_id:ChIJdd4hrwug2EcRmSrV3Vo6llI&destination=place_id:ChIJh1a5WhEMa0gRY1JU4PEam8Q&waypoints=place_id:ChIJPeqVDlONbEgRk4X1zrUsKDs|place_id:ChIJ_WegsaCYc0gRlCypaxXgLjs|&key=YOUR_KEY

有谁知道他们是否停止支持路线优化？

谢谢

google-maps

1 回答

  • 1

    在我看来，当你传入PlaceIds时，这就是DirectionsService中的一个错误 . 我用Javascript API复制了它 . 使用地址有效：

    waypts = [];
  waypts.push({
  location: "Plymouth, UK", // {placeId:"ChIJPeqVDlONbEgRk4X1zrUsKDs"},
  stopover: true
  });
  waypts.push({
  location: "Bournemouth, UK", // {placeId:"ChIJ_WegsaCYc0gRlCypaxXgLjs"},
  stopover: true
  });
  var request = {
    origin: "London, UK", //{placeId:"ChIJdd4hrwug2EcRmSrV3Vo6llI"},
    destination: "Newquay, UK", //{placeId: "ChIJh1a5WhEMa0gRY1JU4PEam8Q"},
    waypoints: waypts,
    optimizeWaypoints: true,
    travelMode: 'DRIVING'
  };

    fiddle using addresses (returns waypoint order=1,0)

    但是相同的位置（我使用这些placeIds来获取上面的地址）使用placeIds不起作用：

    waypts = [];
  waypts.push({
  location: {placeId:"ChIJPeqVDlONbEgRk4X1zrUsKDs"},
  stopover: true
  });
  waypts.push({
  location: {placeId:"ChIJ_WegsaCYc0gRlCypaxXgLjs"},
  stopover: true
  });
  var request = {
    origin: {placeId:"ChIJdd4hrwug2EcRmSrV3Vo6llI"},
    destination: {placeId: "ChIJh1a5WhEMa0gRY1JU4PEam8Q"},
    waypoints: waypts,
    optimizeWaypoints: true,
    travelMode: 'DRIVING'
  };

    fiddle using placeId (returns ZERO_RESULTS）

    可能与问题跟踪器中的此问题有关：Issue 8979: Bug: Can't use combination of placeId and String for origin/destination

    回复于

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