我正在尝试使用ActiveDataProvider作为ActiveDataForm的源代码 . 但是我无法访问这些信息 . 不在视图或控制器内 . 疾病列表ListView是如何工作的 .
我似乎无法弄清楚我哪里出错了 . 即使我得了这样的疾病：
$disease = new Disease();
$disease = Disease::find()->where(['id'=>1]);
我无法访问数据 . 只有当我在控制器中发起新疾病时，我才能使ActiveForm正常工作 .
控制器：
public function actionIndex($id = 1)
{
$disease = new ActiveDataProvider([
'query' => Disease::find()
->where(['id'=>$id]),
'pagination' => [
'pageSize' => 1,
]
]);
$diseaseList = new ActiveDataProvider([
'query' => Disease::find()->orderBy('LOWER(name)'),
'pagination' => [
'pageSize' => 20,
]
]);
return $this->render('index', ['disease' => $disease, 'diseaseList' => $diseaseList]);
}
在我看来：
<?php
echo ListView::widget([
'dataProvider' => $diseaseList,
'itemView' => function($diseaseList, $key, $index, $widget)
{
return
Html::a($diseaseList->name,
Url::toRoute(['disease/index', 'id' => $diseaseList->primaryKey]));
}
]);
?>
<?php
$form = ActiveForm::begin([
'id' => 'disease-form-vertical'
]);
?>
<?= $form->field($disease, 'name') ?>
<?= $form->field($disease, 'description') ?>
<?= $form->field($disease, 'transmission') ?>
<?= $form->field($disease, 'actions') ?>
<?= $form->field($disease, 'report') ?>
<?= $form->field($disease, 'exclusion') ?>
<?= $form->field($disease, 'notes') ?>
<div class="form-group">
<?= Html::submitButton('Login', ['class' => 'btn btn-primary']) ?>
<?= Html::resetButton('Reset', ['class' => 'btn btn-default']) ?>
</div>
<?php ActiveForm::end(); ?>
这是我收到的错误 .
1 回答
这里有问题，这是：
那应该是：
要知道为什么会出现此错误：您正在通过
$disease = Disease::find()->where(['id'=>1])将ActiveQuery传递给ActiveForm，这是错误的 .ActiveForm不接受ActiveQuery.