在Python中查找扩展名为.txt的目录中的所有文件-Java 学习之路

1043

如何在python中找到扩展名为 .txt 的目录中的所有文件？

30 回答

试试这个会在文件夹或文件夹中找到你的所有文件

import glob, os
os.chdir("H:\\wallpaper")# use whatever you directory 

#double\\ no single \

for file in glob.glob("**/*.psd", recursive = True):#your format
    print(file)

回复于 2024-04-27T12:52:50+08:00

path.py是另一种选择：https://github.com/jaraco/path.py

from path import path
p = path('/path/to/the/directory')
for f in p.files(pattern='*.txt'):
    print f

回复于 2024-04-27T12:52:50+08:00

117

这段代码让我的生活更简单 .

import os
fnames = ([file for root, dirs, files in os.walk(dir)
    for file in files
    if file.endswith('.txt') #or file.endswith('.png') or file.endswith('.pdf')
    ])
for fname in fnames: print(fname)

回复于 2024-04-27T12:52:50+08:00

11
要从同一目录中名为“data”的文件夹中获取“.txt”文件名数组，我通常使用以下简单的代码行：
```
import os
fileNames = [fileName for fileName in os.listdir("data") if fileName.endswith(".txt")]
```
回复于 2024-04-27T12:52:50+08:00

import glob
import os

path=os.getcwd()

extensions=('*.py','*.cpp')

for i in extensions:
  for files in glob.glob(i):
     print files

回复于 2024-04-27T12:52:50+08:00

将'dataPath'文件夹中的所有'.txt'文件名称作为Pythonic方式的列表

from os import listdir
from os.path import isfile, join
path = "/dataPath/"
onlyTxtFiles = [f for f in listdir(path) if isfile(join(path, f)) and  f.endswith(".txt")]
print onlyTxtFiles

回复于 2024-04-27T12:52:50+08:00

一个类似于ghostdog的可复制的解决方案：

def get_all_filepaths(root_path, ext):
    """
    Search all files which have a given extension within root_path.

    This ignores the case of the extension and searches subdirectories, too.

    Parameters
    ----------
    root_path : str
    ext : str

    Returns
    -------
    list of str

    Examples
    --------
    >>> get_all_filepaths('/run', '.lock')
    ['/run/unattended-upgrades.lock',
     '/run/mlocate.daily.lock',
     '/run/xtables.lock',
     '/run/mysqld/mysqld.sock.lock',
     '/run/postgresql/.s.PGSQL.5432.lock',
     '/run/network/.ifstate.lock',
     '/run/lock/asound.state.lock']
    """
    import os
    all_files = []
    for root, dirs, files in os.walk(root_path):
        for filename in files:
            if filename.lower().endswith(ext):
                all_files.append(os.path.join(root, filename))
    return all_files

回复于 2024-04-27T12:52:50+08:00

这里有更多相同版本会产生稍微不同的结果：

glob.iglob（）

import glob
for f in glob.iglob("/mydir/*/*.txt"): # generator, search immediate subdirectories 
    print f

glob.glob1（）

print glob.glob1("/mydir", "*.tx?")  # literal_directory, basename_pattern

fnmatch.filter（）

import fnmatch, os
print fnmatch.filter(os.listdir("/mydir"), "*.tx?") # include dot-files

回复于 2024-04-27T12:52:50+08:00

Python有所有工具可以做到这一点：

import os

the_dir = 'the_dir_that_want_to_search_in'
all_txt_files = filter(lambda x: x.endswith('.txt'), os.listdir(the_dir))

回复于 2024-04-27T12:52:50+08:00

这样的东西会起作用：

>>> import os
>>> path = '/usr/share/cups/charmaps'
>>> text_files = [f for f in os.listdir(path) if f.endswith('.txt')]
>>> text_files
['euc-cn.txt', 'euc-jp.txt', 'euc-kr.txt', 'euc-tw.txt', ... 'windows-950.txt']

回复于 2024-04-27T12:52:50+08:00

import os
import sys 

if len(sys.argv)==2:
    print('no params')
    sys.exit(1)

dir = sys.argv[1]
mask= sys.argv[2]

files = os.listdir(dir); 

res = filter(lambda x: x.endswith(mask), files); 

print res

回复于 2024-04-27T12:52:50+08:00

1
我建议你使用fnmatch和上面的方法 . 通过这种方式，您可以找到以下任何一项：
- 姓名 . txt ;
- 姓名 . TXT ;
- 姓名 . Txt
.
```
import fnmatch
import os

    for file in os.listdir("/Users/Johnny/Desktop/MyTXTfolder"):
        if fnmatch.fnmatch(file.upper(), '*.TXT'):
            print(file)
```
回复于 2024-04-27T12:52:50+08:00

你可以使用glob：

import glob, os
os.chdir("/mydir")
for file in glob.glob("*.txt"):
    print(file)

或者只是os.listdir：

import os
for file in os.listdir("/mydir"):
    if file.endswith(".txt"):
        print(os.path.join("/mydir", file))

或者如果要遍历目录，请使用os.walk：

import os
for root, dirs, files in os.walk("/mydir"):
    for file in files:
        if file.endswith(".txt"):
             print(os.path.join(root, file))

回复于 2024-04-27T12:52:50+08:00

这是 extend() 的一个

types = ('*.jpg', '*.png')
images_list = []
for files in types:
    images_list.extend(glob.glob(os.path.join(path, files)))

回复于 2024-04-27T12:52:50+08:00

190

许多用户回复了 os.walk 答案，其中包括所有文件以及所有目录和子目录及其文件 .

import os


def files_in_dir(path, extension=''):
    """
       Generator: yields all of the files in <path> ending with
       <extension>

       \param   path       Absolute or relative path to inspect,
       \param   extension  [optional] Only yield files matching this,

       \yield              [filenames]
    """


    for _, dirs, files in os.walk(path):
        dirs[:] = []  # do not recurse directories.
        yield from [f for f in files if f.endswith(extension)]

# Example: print all the .py files in './python'
for filename in files_in_dir('./python', '*.py'):
    print("-", filename)

或者对于不需要发电机的一次性：

path, ext = "./python", ext = ".py"
for _, _, dirfiles in os.walk(path):
    matches = (f for f in dirfiles if f.endswith(ext))
    break

for filename in matches:
    print("-", filename)

如果您要将匹配用于其他内容，您可能希望将其设置为列表而不是生成器表达式：

matches = [f for f in dirfiles if f.endswith(ext)]

回复于 2024-04-27T12:52:50+08:00

您可以尝试此代码

import glob
import os
filenames_without_extension = [os.path.basename(c).split('.')[0:1][0] for c in glob.glob('your/files/dir/*.txt')]
filenames_with_extension = [os.path.basename(c) for c in glob.glob('your/files/dir/*.txt')]

回复于 2024-04-27T12:52:50+08:00

如果文件夹包含大量文件或内存是约束，请考虑使用生成器：

def yield_files_with_extensions(folder_path, file_extension):
   for _, _, files in os.walk(folder_path):
       for file in files:
           if file.endswith(file_extension):
               yield file

选项A：迭代

for f in yield_files_with_extensions('.', '.txt'): 
    print(f)

选项B：全部获取

files = [f for f in yield_files_with_extensions('.', '.txt')]

回复于 2024-04-27T12:52:50+08:00

Python v3.5

在递归函数中使用os.scandir的快速方法 . 在文件夹和子文件夹中搜索具有指定扩展名的所有文件 .

import os

def findFilesInFolder(path, pathList, extension, subFolders = True):
    """  Recursive function to find all files of an extension type in a folder (and optionally in all subfolders too)

    path:        Base directory to find files
    pathList:    A list that stores all paths
    extension:   File extension to find
    subFolders:  Bool.  If True, find files in all subfolders under path. If False, only searches files in the specified folder
    """

    try:   # Trapping a OSError:  File permissions problem I believe
        for entry in os.scandir(path):
            if entry.is_file() and entry.path.endswith(extension):
                pathList.append(entry.path)
            elif entry.is_dir() and subFolders:   # if its a directory, then repeat process as a nested function
                pathList = findFilesInFolder(entry.path, pathList, extension, subFolders)
    except OSError:
        print('Cannot access ' + path +'. Probably a permissions error')

    return pathList

dir_name = r'J:\myDirectory'
extension = ".txt"

pathList = []
pathList = findFilesInFolder(dir_name, pathList, extension, True)

回复于 2024-04-27T12:52:50+08:00

2
你可以简单地使用pathlib s glob 1：
```
import pathlib

list(pathlib.Path('your_directory').glob('*.txt'))
```
或循环：
```
for txt_file in pathlib.Path('your_directory').glob('*.txt'):
    # do something with "txt_file"
```
如果你想要它递归你可以使用 .glob('**/*.txt)

1 pathlib 模块包含在python 3.4的标准库中 . 但是，即使在较旧的Python版本上（即使用 conda 或 pip ），您也可以安装该模块的后端端口：pathlib和pathlib2 .
回复于 2024-04-27T12:52:50+08:00

这样的事情应该可以胜任

for root, dirs, files in os.walk(directory):
    for file in files:
        if file.endswith('.txt'):
            print file

回复于 2024-04-27T12:52:50+08:00

import os

path = 'mypath/path' 
files = os.listdir(path)

files_txt = [i for i in files if i.endswith('.txt')]

回复于 2024-04-27T12:52:50+08:00

使用glob .

>>> import glob
>>> glob.glob('./*.txt')
['./outline.txt', './pip-log.txt', './test.txt', './testingvim.txt']

回复于 2024-04-27T12:52:50+08:00

我做了一个测试（Python 3.6.4，W7x64），看看哪个解决方案对于一个文件夹，没有子目录来说是最快的，以获取具有特定扩展名的文件的完整文件路径列表 .

为了缩短它，对于这个任务来说， os.listdir() 是最快的，并且速度是次佳的1.7倍： os.walk() （有休息！），2.7倍于 pathlib ，比 os.scandir() 快3.2倍，比 glob 快3.3倍 .
请记住，当您需要递归结果时，这些结果会发生变化 . 如果你复制/粘贴下面的一个方法，请添加.lower（），否则在搜索.ext时找不到.EXT .

import os
import pathlib
import timeit
import glob

def a():
    path = pathlib.Path().cwd()
    list_sqlite_files = [str(f) for f in path.glob("*.sqlite")]

def b(): 
    path = os.getcwd()
    list_sqlite_files = [f.path for f in os.scandir(path) if os.path.splitext(f)[1] == ".sqlite"]

def c():
    path = os.getcwd()
    list_sqlite_files = [os.path.join(path, f) for f in os.listdir(path) if f.endswith(".sqlite")]

def d():
    path = os.getcwd()
    os.chdir(path)
    list_sqlite_files = [os.path.join(path, f) for f in glob.glob("*.sqlite")]

def e():
    path = os.getcwd()
    list_sqlite_files = [os.path.join(path, f) for f in glob.glob1(str(path), "*.sqlite")]

def f():
    path = os.getcwd()
    list_sqlite_files = []
    for root, dirs, files in os.walk(path):
        for file in files:
            if file.endswith(".sqlite"):
                list_sqlite_files.append( os.path.join(root, file) )
        break



print(timeit.timeit(a, number=1000))
print(timeit.timeit(b, number=1000))
print(timeit.timeit(c, number=1000))
print(timeit.timeit(d, number=1000))
print(timeit.timeit(e, number=1000))
print(timeit.timeit(f, number=1000))

结果：

# Python 3.6.4
0.431
0.515
0.161
0.548
0.537
0.274

回复于 2024-04-27T12:52:50+08:00

使用 for 循环的简单方法：

import os

dir = ["e","x","e"]

p = os.listdir('E:')  #path

for n in range(len(p)):
   name = p[n]
   myfile = [name[-3],name[-2],name[-1]]  #for .txt
   if myfile == dir :
      print(name)
   else:
      print("nops")

虽然这可以更加通用化 .

回复于 2024-04-27T12:52:50+08:00

1772

使用Python OS模块查找具有特定扩展名的文件 .

这里有一个简单的例子：

import os

# This is the path where you want to search
path = r'd:'  

# this is extension you want to detect
extension = '.txt'   # this can be : .jpg  .png  .xls  .log .....

for root, dirs_list, files_list in os.walk(path):
    for file_name in files_list:
        if os.path.splitext(file_name)[-1] == extension:
            file_name_path = os.path.join(root, file_name)
            print file_name
            print file_name_path   # This is the full path of the filter file

回复于 2024-04-27T12:52:50+08:00

你可以试试这段代码：

import glob
import os

os.chdir("D:\...\DirName")
filename_arr={}
i=0
for files in glob.glob("*.txt"):
    filename_arr[i] = files
    i= i+1

for key,value in filename_arr.items():
    print key , value

回复于 2024-04-27T12:52:50+08:00

使用fnmatch：https://docs.python.org/2/library/fnmatch.html

import fnmatch
import os

for file in os.listdir('.'):
    if fnmatch.fnmatch(file, '*.txt'):
        print file

回复于 2024-04-27T12:52:50+08:00

我喜欢os.walk()：

import os, os.path

for root, dirs, files in os.walk(dir):
    for f in files:
        fullpath = os.path.join(root, f)
        if os.path.splitext(fullpath)[1] == '.txt':
            print fullpath

或者使用发电机：

import os, os.path

fileiter = (os.path.join(root, f)
    for root, _, files in os.walk(dir)
    for f in files)
txtfileiter = (f for f in fileiter if os.path.splitext(f)[1] == '.txt')
for txt in txtfileiter:
    print txt

回复于 2024-04-27T12:52:50+08:00

import glob,os

data_dir = 'data_folder/'
file_dir_extension = os.path.join(data_dir, '*.txt')

for file_name in glob.glob(file_dir_extension):
    if file_name.endswith('.txt'):
        print file_name

为了我 . 这很经典 .

回复于 2024-04-27T12:52:50+08:00

具有子目录的功能解决方案：

from fnmatch import filter
from functools import partial
from itertools import chain
from os import path, walk

print(*chain(*(map(partial(path.join, root), filter(filenames, "*.txt")) for root, _, filenames in walk("mydir"))))

回复于 2024-04-27T12:52:50+08:00

在Python中查找扩展名为.txt的目录中的所有文件

30 回答

glob.iglob（）

glob.glob1（）

fnmatch.filter（）

Python v3.5

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