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在Keras中构建具有嵌入层的LSTM网络

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我想创建一个由嵌入层组成的Keras模型,然后是两个带有dropout 0.5的LSTM,最后是一个带有softmax激活的密集层 .

第一个LSTM应该将顺序输出传播到第二层,而在第二个层中,我只对处理整个序列后获取LSTM的隐藏状态感兴趣 .

我尝试了以下方法:

sentence_indices = Input(input_shape, dtype = 'int32')

embedding_layer = pretrained_embedding_layer(word_to_vec_map, word_to_index)

embeddings = embedding_layer(sentence_indices)
# Propagate the embeddings through an LSTM layer with 128-dimensional hidden state
X = LSTM(128, return_sequences=True, dropout = 0.5)(embeddings)

# Propagate X trough another LSTM layer with 128-dimensional hidden state
X = LSTM(128, return_sequences=False, return_state=True, dropout = 0.5)(X)

# Propagate X through a Dense layer with softmax activation to get back a batch of 5-dimensional vectors.
X = Dense(5, activation='softmax')(X)

# Create Model instance which converts sentence_indices into X.
model = Model(inputs=[sentence_indices], outputs=[X])

但是我收到以下错误:

ValueError: Layer dense_5 expects 1 inputs, but it received 3 input tensors. Input received: [<tf.Tensor 'lstm_10/TensorArrayReadV3:0' shape=(?, 128) dtype=float32>, <tf.Tensor 'lstm_10/while/Exit_2:0' shape=(?, 128) dtype=float32>, <tf.Tensor 'lstm_10/while/Exit_3:0' shape=(?, 128) dtype=float32>]

很明显,LSTM没有返回我期望的形状的输出 . 我该如何解决?

1 回答

  • 1

    如果设置 return_state=True ,则 LSTM(...)(X) 将返回三个内容:输出,最后隐藏状态和最后一个单元状态 .

    所以不是 X = LSTM(128, return_sequences=False, return_state=True, dropout = 0.5)(X) ,而是 X, h, c = LSTM(128, return_sequences=False, return_state=True, dropout = 0.5)(X)

    有关示例,请参阅here .

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