如何在HttpURLConnection中发送PUT，DELETE HTTP请求？

9 回答

• 8

  要执行HTTP PUT：

  URL url = new URL("http://www.example.com/resource");
  HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
  httpCon.setDoOutput(true);
  httpCon.setRequestMethod("PUT");
  OutputStreamWriter out = new OutputStreamWriter(
      httpCon.getOutputStream());
  out.write("Resource content");
  out.close();
  httpCon.getInputStream();
  

  要执行HTTP DELETE：

  URL url = new URL("http://www.example.com/resource");
  HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
  httpCon.setDoOutput(true);
  httpCon.setRequestProperty(
      "Content-Type", "application/x-www-form-urlencoded" );
  httpCon.setRequestMethod("DELETE");
  httpCon.connect();
  

  回复于 2024-04-26T14:34:09+08:00
• 0

  这是它对我有用的方式：

  HttpURLConnection connection = (HttpURLConnection) url.openConnection();
  connection.setRequestMethod("DELETE");
  int responseCode = connection.getResponseCode();
  

  回复于 2024-04-26T14:34:09+08:00
• 3

  public  HttpURLConnection getHttpConnection(String url, String type){
          URL uri = null;
          HttpURLConnection con = null;
          try{
              uri = new URL(url);
              con = (HttpURLConnection) uri.openConnection();
              con.setRequestMethod(type); //type: POST, PUT, DELETE, GET
              con.setDoOutput(true);
              con.setDoInput(true);
              con.setConnectTimeout(60000); //60 secs
              con.setReadTimeout(60000); //60 secs
              con.setRequestProperty("Accept-Encoding", "Your Encoding");
              con.setRequestProperty("Content-Type", "Your Encoding");
          }catch(Exception e){
              logger.info( "connection i/o failed" );
          }
          return con;
  }
  

  然后在你的代码中：

  public void yourmethod(String url, String type, String reqbody){
      HttpURLConnection con = null;
      String result = null;
      try {
          con = conUtil.getHttpConnection( url , type);
      //you can add any request body here if you want to post
           if( reqbody != null){  
                  con.setDoInput(true);
                  con.setDoOutput(true);
                  DataOutputStream out = new  DataOutputStream(con.getOutputStream());
                  out.writeBytes(reqbody);
                  out.flush();
                  out.close();
              }
          con.connect();
          BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
          String temp = null;
          StringBuilder sb = new StringBuilder();
          while((temp = in.readLine()) != null){
              sb.append(temp).append(" ");
          }
          result = sb.toString();
          in.close();
      } catch (IOException e) {
          // TODO Auto-generated catch block
          e.printStackTrace();
          logger.error(e.getMessage());
      }
  //result is the response you get from the remote side
  }
  

  回复于 2024-04-26T14:34:09+08:00
• 0

  我同意@adietisheim和其他建议HttpClient的人 .

  我花了很多时间尝试使用HttpURLConnection进行简单的休息服务，并且它没有说服我，之后我尝试使用HttpClient，它真的更容易，可以理解和更好 .

  进行put http调用的代码示例如下：

  DefaultHttpClient httpClient = new DefaultHttpClient();
  
  HttpPut putRequest = new HttpPut(URI);
  
  StringEntity input = new StringEntity(XML);
  input.setContentType(CONTENT_TYPE);
  
  putRequest.setEntity(input);
  HttpResponse response = httpClient.execute(putRequest);
  

  回复于 2024-04-26T14:34:09+08:00
• 9

  UrlConnection是一个难以使用的API . HttpClient是迄今为止更好的API，它将使您免于浪费时间搜索如何实现某些事情，例如stackoverflow问题完全说明 . 我在几个REST客户端中使用了jdk HttpUrlConnection之后编写了这个 . 此外，当谈到可伸缩性功能（如线程池，连接池等）时，HttpClient非常出色

  回复于 2024-04-26T14:34:09+08:00
• 3

  要正确执行HTML中的PUT，您必须使用try / catch包围它：

  try {
      url = new URL("http://www.example.com/resource");
      HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
      httpCon.setDoOutput(true);
      httpCon.setRequestMethod("PUT");
      OutputStreamWriter out = new OutputStreamWriter(
          httpCon.getOutputStream());
      out.write("Resource content");
      out.close();
      httpCon.getInputStream();
  } catch (MalformedURLException e) {
      e.printStackTrace();
  } catch (ProtocolException e) {
      e.printStackTrace();
  } catch (IOException e) {
      e.printStackTrace();
  }
  

  回复于 2024-04-26T14:34:09+08:00
• 20

  我会推荐Apache HTTPClient .

  • How to do a PUT.

  • How to do a DELETE.

  回复于 2024-04-26T14:34:09+08:00
• 0

  即使是休息模板也可以选择：

  String payload = "<?xml version=\"1.0\" encoding=\"UTF-8\"?<CourierServiceabilityRequest>....";
      RestTemplate rest = new RestTemplate();
  
      HttpHeaders headers = new HttpHeaders();
      headers.add("Content-Type", "application/xml");
      headers.add("Accept", "*/*");
      HttpEntity<String> requestEntity = new HttpEntity<String>(payload, headers);
      ResponseEntity<String> responseEntity =
              rest.exchange(url, HttpMethod.PUT, requestEntity, String.class);
  
       responseEntity.getBody().toString();
  

  回复于 2024-04-26T14:34:09+08:00
• 160

  有一个简单的删除和放置请求的方法，你可以通过添加“ _method " parameter to your post request and write " PUT " or " DELETE ”来实现它的 Value ！

  回复于 2024-04-26T14:34:09+08:00