我想获得Sample的Project名称 . 它应该在self.args中,因为我的urls.py看起来像那样(有很多网址,所以我只会发布重要内容):
项目/ urls.py
app_name = 'projects'
urlpatterns = [
url(r"^$", ProjectListView.as_view(), name="projects_list"),
url(r"^(\w+)/robjects/", include("robjects.urls")),
url(r"^(\w+)/tags/$", TagsListView.as_view(), name="tag_list"),
...
]
robjects / urls.py
app_name="robjects"
urlpatterns = [
...
url(r'^(?P<pk>[0-9]+)/samples/', include("samples.urls")),
]
样本/ urls.py
app_name="samples"
urlpatterns = [
url(r'^list/$', SampleListView.as_view(), name='sample_list_view'),
url(r'^create/$', SampleCreateView.as_view(), name='sample_create_view'),
url(r'^(?P<sample_id>[0-9]+)/update/$', SampleUpdateView.as_view(), name='sample_update'),
url(r'^(?P<sample_id>[0-9]+)/delete/$', SampleDeleteView.as_view(), name='sample_delete'),
]
我想获取project_name,即projects / urls.py的'(\ w)'部分 . 为此,我在samples / views.py中编写了该代码 . 我试着做project_name = self.args [0],但我的args是空的 .
class SampleListView(ListView):model = Sample template_name =“samples / samples_list.html”
def get(self, request, *args, **kwargs):
"""A base view for displaying a list of objects."""
# check if project exists
try:
pk = kwargs['pk']
robject = Robject.objects.get(id=pk)
# add project to view attributes
self.robject = robject
except Robject.DoesNotExist:
raise Http404
print(self.args) # it should be a project name here
return super(SampleListView, self).get(request, *args, **kwargs)
def get_queryset(self, *args, **kwargs):
"""
Overwrite orginal qs and add filtering by robject
"""
# original queryset
qs = super().get_queryset(*args, **kwargs)
print('args, ',self.args)
print('kwargs', self.kwargs)
pk = self.kwargs['pk']
robject = Robject.objects.get(id=pk)
return qs.filter(robject=self.robject)
这是输出:
args, ()
kwargs {'pk': '27'}
我想通过robject_id和project_name过滤我的qs,对于robject_id,它可以正常工作 . 我不知道如何获取project_name进行过滤 .
此外,我不得不说,在标签(“没有包含在网址中”)中我使用self.argss [0]进行了它并且它可以工作,但只能形成标签ListView .
代码如下:
class TagsListView(LoginRequiredMixin, ListView):
model = Tag
template_name = "tags/tag_list.html"
def get(self, request, *args, **kwargs):
"""A base view for displaying a list of objects."""
# check if project exists
try:
project = Project.objects.get(name=args[0]) # it works fine
# add project to view attributes
self.project = project
except Project.DoesNotExist:
raise Http404
return super(TagsListView, self).get(request,*args, **kwargs)
这是我发现的:
当我像这样定义我的URL时:
url(r“^(\ w)/ robjects / samples / $”,SampleListView.as_view(),name ='sample_list_view'),
所有的人 . 在我的args中是project_name,我可以通过self.args [0]捕获它
但是当我加上我的args是空的时候,
url(r“^(\ w)/ robjects /(?P <pk> [0-9])/ samples / $”,SampleListView.as_view(),name ='sample_list_view'),
当我定义两个这样的kwargs时:
url(r"^(?P<project_name>[\w\-]+)/robjects/(?P<pk>[0-9]+)/samples/list/$",SampleListView.as_view(), name='sample_list_view'),
args空 - 我的预期,kwargs两者都可以并传递给视图
它是一个Django错误还是有任何方法可以使用self.args?他们被kwargs淹没了吗?
感谢帮助 !
1 回答
它看起来像一个bug . 我测试了它,当你将args和kwargs传递到你的网址时:
然后ListView返回args的空元组(它不应该) . 当你只将args或kwargs传递给url时它会起作用 .