我是Volley的新手,我正在尝试使用Post请求
JsonArrayRequest
从我在stackoverflow上找到的很多答案,我尝试如下 -
private void getCounts() {
String url = "http://192.168.1.100/json/count.php";
JsonArrayRequest req = new JsonArrayRequest(url,
new Response.Listener<JSONArray>() {
@Override
public void onResponse(JSONArray response) {
Log.d(TAG, response.toString());
hidepDialog();
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.d(TAG, "Error: " + error.getMessage());
Log.d(TAG, "Error: " + error.getMessage());
Toast.makeText(getApplicationContext(),
error.getMessage(), Toast.LENGTH_SHORT).show();
hidepDialog();
}
}) {
@Override
protected Map<String, String> getParams() {
Map<String, String> params = new HashMap<String, String>();
params.put("LastUpdatedAt", "0");
return params;
}
@Override
public Map<String, String> getHeaders() throws AuthFailureError {
HashMap<String, String> headers = new HashMap<String, String>();
headers.put("Content-Type", "application/json; charset=utf-8");
headers.put("User-agent", "My useragent");
return headers;
}
@Override
public byte[] getBody() {
Map<String, String> params = new HashMap<String, String>();
params.put("LastUpdatedAt", "0");
if (params != null && params.size() > 0) {
Log.d(TAG, encodeParameters(params, getParamsEncoding()).toString());
return encodeParameters(params, getParamsEncoding());
}
return null;
}
protected byte[] encodeParameters(Map<String, String> params, String paramsEncoding) {
StringBuilder encodedParams = new StringBuilder();
try {
for (Map.Entry<String, String> entry : params.entrySet()) {
encodedParams.append(URLEncoder.encode(entry.getKey(), paramsEncoding));
encodedParams.append('=');
encodedParams.append(URLEncoder.encode(entry.getValue(), paramsEncoding));
encodedParams.append('&');
}
return encodedParams.toString().getBytes(paramsEncoding);
} catch (UnsupportedEncodingException uee) {
throw new RuntimeException("Encoding not supported: " + paramsEncoding, uee);
}
}
};
AppController.getInstance().addToRequestQueue(req);
}
As one can see, I have tried both, getParams() and getBody() to send LastUpdatedAt as Post request, but no matter what I try the value is not posted and returns null on server.
我甚至尝试使用 JsonArrayRequest(Request.Method.POST, ...
并在请求中发送'params'作为JsonObject,但即使这两个也不起作用 .
在其中一个similar question中,建议使用以下类 -
public class CustomJsonRequest extends Request {
Map<String, String> params;
private Response.Listener listener;
public CustomJsonRequest(int requestMethod, String url, Map<String, String> params,
Response.Listener responseListener, Response.ErrorListener errorListener) {
super(requestMethod, url, errorListener);
this.params = params;
this.listener = responseListener;
}
@Override
protected void deliverResponse(Object response) {
listener.onResponse(response);
}
@Override
public Map<String, String> getParams() throws AuthFailureError {
return params;
}
@Override
protected Response parseNetworkResponse(NetworkResponse response) {
try {
String jsonString = new String(response.data, HttpHeaderParser.parseCharset(response.headers));
return Response.success(new JSONObject(jsonString),
HttpHeaderParser.parseCacheHeaders(response));
} catch (UnsupportedEncodingException e) {
return Response.error(new ParseError(e));
} catch (JSONException je) {
return Response.error(new ParseError(je));
}
}
}
但是我无法使用响应列表器 createRequestSuccessListener
及其错误监听器 .
在同样的问题中,建议使用以下构造函数 -
public JsonArrayRequest(int method, String url, JSONObject jsonRequest,
Listener<JSONArray> listener, ErrorListener errorListener) {
super(method, url, (jsonRequest == null) ? null : jsonRequest.toString(),
listener, errorListener);
}
但是,我无法弄清楚如何让它发挥作用?
1 回答
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