我的要求是从某个网站下载abc.zip文件http://clientdownload.xyz.com/Documents/abc.zip
对于这个活动,我编写了一个python脚本,如下所示:
url_to_check = 'http://clientdownload.xyz.com/Documents/abc.zip'
username = "user"
password = "pwd"
p = urllib2.HTTPPasswordMgrWithDefaultRealm()
p.add_password(None, url_to_check, username, password)
handler = urllib2.HTTPBasicAuthHandler(p)
opener = urllib2.build_opener(handler)
urllib2.install_opener(opener)
zip_file = urllib2.urlopen(url_to_check).read()
file_name = 'somefile.zip'
meta = zip_file.info()
file_size = int(meta.getheaders("Content-Length")[0])
print "Downloading: %s Bytes: %s" % (file_name, file_size)
with open(file_name, 'wb') as dwn_file:
dwn_file.write(zip_file.read())
我在运行脚本时遇到以下错误:
文件“updateCheck.py”,第68行,在check_update zip_file = urllib2.urlopen(url_to_check).read()文件“/usr/lib/python2.7/urllib2.py”,第126行,在urlopen中返回_opener.open (url,data,timeout)文件“/usr/lib/python2.7/urllib2.py”,第406行,打开响应= meth(req,response)文件“/usr/lib/python2.7/urllib2.py “,第519行,在http_response'http',请求,响应,代码,消息,hdrs)文件”/usr/lib/python2.7/urllib2.py“,第444行,错误返回self._call_chain(* args)文件“/usr/lib/python2.7/urllib2.py”,第378行,在_call_chain中结果= func(* args)文件“/usr/lib/python2.7/urllib2.py”,第527行,在http_error_default中HTTPError(req.get_full_url(),code,msg,hdrs,fp)urllib2.HTTPError:HTTP错误401:未经授权
我已正确地给出了用户名和密码,但它会引发未经授权的错误 .
当我尝试使用带有 -http-user and --ask-password
选项的wget链接下载它时,我可以下载该文件 .
同样使用相同的脚本,我可以正确地从其他服务器下载文件 .
我运行此脚本以获取更多信息:
import urllib2, re, time, sys
theurl='http://clientdownload.xxx.com/Documents/Forms/AllItems.aspx'
req = urllib2.Request(theurl)
try:
handle = urllib2.urlopen(req)
except IOError, e:
if hasattr(e, 'code'):
if e.code != 401:
print 'We got another error'
print e.code
else:
print e.headers
print e.headers['www-authenticate']
我收到了以下信息:
Content-Type: text/html; charset=utf-8
Server: Microsoft-IIS/7.5
SPRequestGuid: 939bad00-40b7-49b9-bbbc-99d0267a1004
X-SharePointHealthScore: 0
WWW-Authenticate: NTLM
X-Powered-By: ASP.NET
MicrosoftSharePointTeamServices: 14.0.0.6029
Date: Wed, 12 Feb 2014 13:14:19 GMT
Connection: close
Content-Length: 16
NTLM
1 回答
您可以考虑使用requests使其更容易通过HTTP进行交互 . 在您的情况下,通过安装requests-ntlm(
requests
的插件),您将以更透明的方式获得NTLM authentication:r
保留响应,包括error codes和headers(特别针对您的情况r.headers.get('Content-Length')[0]
)