首页 文章

猜猜文字游戏：秘密词的猜测没有被接受

提问于
浏览 次
0

我在Python 3.x工作并且相当新，所以我希望我所要求的是有道理的 . 我应该专注于这个猜词游戏的循环和字符串 . 这是我到目前为止的（混乱/冗长/混乱）代码：

import sys
import random

def Main():
    PlayAgain = "y"
    print("COP 1000 Project 4 - Courtney Kasonic - Guess the Word Game")
    print("I'm thinking of a word; can you guess what it is?")
    while PlayAgain == "y":
        Words = "apple alphabet boomarang cat catharsis define decide elephant fish goat horizon igloo jackelope ketchup loop limousine monkey night octopus potato quick rebel separate test underway violin world yellow zebra".split()
        SecretWord = random.choice(Words)
        MissedLetters = ""
        CorrectLetters = ""
        ChosenWord = GetWord(Words)
        Guess = FiveLetters(CorrectLetters+MissedLetters)
        for Guess in ChosenWord:
            CorrectLetters = CorrectLetters + Guess
        ShowWord(CorrectLetters, ChosenWord)
        for i in ChosenWord:
            CLetters = ""
            if Guess in ChosenWord:
                Blanks = "_" * len(SecretWord)
                for i in range(len(SecretWord)):
                    if SecretWord[i] in CLetters:
                        Blanks = Blanks[i] + SecretWord[i]
                        print(Blanks)
                        print(CLetters)

def GetWord(List):
    SecretWord = random.choice(List)
    return(SecretWord)

**def FiveLetters(LettersGuessed):
    a = 2
    if a > 1:
        print("Enter five letters to check: ",end="")
        Guess = input()
        if len(Guess) != 5:
            print("Please enter five letters.")
        elif Guess in LettersGuessed:
            print("You already guessed that letter.")
        elif Guess not in "abcdefghijklmnopqrstuvwxyz":
            print("Please enter a letter.")
        else:
            return(Guess)**

def ShowWord(CLetters, SecretWord):
    print("\nHere is the word showing the letters that you guessed:\n")
    CLetters = ""
    Blanks = "_" * len(SecretWord)
    for i in range(len(SecretWord)):
        if SecretWord[i] in CLetters:
            Blanks = Blanks[i] + SecretWord[i]
            print(Blanks)
            print(CLetters)
        return(Blanks, SecretWord, CLetters)

def CheckLetters(Letters):
    Letters = "a b c d e f g h i j k l m n o p q r s t u v w x y z".split()
    for Letters in Word:
        print(Letters)
    return(Letters)

Main()

粗体区是我遇到问题的地方 . 只能输入五个字母来“检查”以查看它们是否在保密字中 . 它只接受像“abcde”这样的输入 . 它不接受像“aaaaa”或“muihi”这样的输入，即它不接受不按顺序或具有多个相同字母的猜测 .

我也有下划线的问题 . 不确定我的代码是否正确 . 正确猜测的字母不会取代适当的下划线 .

例如：秘密词=狗 . 如果我猜字母“mopfe”（虽然因为上面的问题我不能）然后它会打印出“_ _ _”而没有“o” .

python

1 回答

  • 1

    假设您不想失败，您将不可避免地提出更多问题 . 如果你在StackOverflow上问这些问题，你应该read the FAQ . 由于您使用的是python，您可能还应该阅读样式指南（即PEP 8），评论中提到了它 . 此代码虽然不完整，但可以帮助您入门 .

    import sys
import random

def main():
    play_again = "y"
    print("COP 1000 Project 4 - Courtney Kasonic - Guess the Word Game")
    print("I'm thinking of a word; can you guess what it is?")

    words = "apple alphabet boomarang cat catharsis define decide elephant fish goat horizon igloo jackelope ketchup loop limousine monkey night octopus potato quick rebel separate test underway violin world yellow zebra".split()
    secret_word = random.choice(words)
    correct_letters = ""

    while play_again == "y":

        guess = five_letters(correct_letters)

        for letter in guess:
            if letter in secret_word:
                correct_letters += letter

        show_word(correct_letters, secret_word)

def five_letters(letters_guessed):

        guess = raw_input("Enter five letters to check: ")

        if len(guess) != 5:
            print("Please enter five letters.")
        elif guess in letters_guessed:
            print("You already guessed that letter.")
        elif guess not in "abcdefghijklmnopqrstuvwxyz":
            print("Please enter a letter.")
        else:
            return guess

def show_word(correct_letters, secret_word):
    print("\nHere is the word showing the letters that you guessed:\n")
    word_display = ""

    for index, letter in enumerate(secret_word):
        if letter in correct_letters:
            word_display += letter
        else:
            word_display += "_"

    print word_display

if __name__ == "__main__":

    main()
    回复于

相关问题