我试图在linux上使用IPv6套接字使用IPv4映射的IPv6地址连接到IPv4地址(debian-lenny-64 2.6.26-2-amd64)
#include <sys/types.h>
#include <sys/socket.h>
#include <netdb.h>
#include <errno.h>
#include <stdlib.h>
#include <stdio.h>
int main(int argc, void **argv)
{
struct addrinfo *sa;
struct addrinfo *ra;
int err = getaddrinfo("2001:DB8::2", 0, 0, &sa);
int fd = socket(sa->ai_family, SOCK_DGRAM, 0);
int v6only = 0;
err = setsockopt(fd, IPPROTO_IPV6, IPV6_V6ONLY, (void *)&v6only, sizeof(v6only));
err = bind(fd, sa->ai_addr, sa->ai_addrlen);
err = getaddrinfo("::ffff:192.168.0.1", "9", 0, &ra);
// err = getaddrinfo("2001:DB8::1", "9", 0, &ra);
// err = getaddrinfo("::ffff:127.0.0.1", "9", 0, &ra);
err = connect(fd, (struct sockaddr *)ra->ai_addr, sizeof(struct sockaddr_in6));
}
(我已从粘贴的代码中删除了错误测试)
2001:DB8 :: 2和192.168.0.2是本地地址(两者都在同一个接口上) .
2001:DB8 :: 1和192.168.0.1是远程地址(两者都在同一个接口上) .
我更改了连接呼叫的远程地址并获得以下内容:
-
connect to :: ffff:127.0.0.1 success(localhost)
-
连接到2001:DB8 :: 1成功(远程IPv6地址)
-
connect to :: ffff:192.168.0.2 success(本地IPv4地址)
-
connect to :: ffff:192.168.0.1 failure(22无效参数 - 远程IPv4)
如果我改为做IPv4连接,那么连接也可以工作 .
我认为在某个地方必须存在路由问题,但我无法解决我需要改变的问题 . 首先,我理论上应该能够做到这一点吗?
出了什么问题?
1 回答
.