Python - 如何排除星期六 . 和太阳从几个星期

4 回答

• 0

  这是查找上一个工作日数量的一种方法：

  请注意，年，月，日的类型转换为 int .

  import calendar
  
  year = int(input('Year: '))
  month = int(input('Month: '))
  day = int(input('Day: '))
  
  full_wks = day / 7
  extra_days = day % 7
  
  first_day = calendar.weekday(year, month, 1)
  if first_day >= 5:              # if month begins on a weekend
      weekend = 7 - first_day     # yields 1 if Sunday, 2 if Saturday
      extra_days -= weekend
  
  weekdays = full_wks * 5 + extra_days
  
  ordinal = lambda n: "{}{}".format(n, 'tsnrhtdd'[n%5*(n%100^15>4>n%10)::4])
  
  print "{}/{} is the {} weekday in the month.".format(month, day, ordinal(weekdays))
  

  输出：

  Year: 2018
  Month: 7
  Day: 20
  7/20 is the 15th weekday in the month.
  

  Code Golf上xsot的序号转换 .

  回复于 2024-05-17T17:28:30+08:00
• 1

  我在大约10分钟内做了一个简单的解决方案 . 我的方法很大程度上依赖于列表推导和字符串方法，例如join和split，所以如果你不熟悉它们，我建议你查看它们 . 首先将结果拆分为行，tittle需要被删除，其他行需要删除最后一个字符 .

  通过使用strip（）方法在行的乞讨处删除空白，然后预先添加两个空格来接收第一行 .

  在周末使用列表推导仅包含每行的前15个字符 .

  最后一部分是最难的 . 我的想法是计算格式化日历中有多少天数 . 首先将带有日期数的所有行放入一个大行，然后用空格分割行以获得所有日期数的列表，最后使用列表的大小 .

  import calendar
  
  year = float(input('Year: '))
  month = float(input('Month: '))
  input_year = []
  input_month = []
  
  if year >= 1000 and year <=3000:
      input_year.append(year)
  if month >= 1 and month <=12:
      input_month.append(month)
  
  cal_format = calendar.TextCalendar(calendar.MONDAY)
  result_cal = cal_format.formatmonth(int(input_year[0]), int(input_month[0]))
  
  lines = result_cal.split("\n") # Split result_cal into a list of lines
  title_line = lines[0] # Save first line, we want to edit this differently
  title_line = "  " + title_line.strip() # Change the indentation of the title line
  
  
  lines = lines[1:] # Now select lines below the first 
  lines = [line[:3*5] for line in lines] # Only Keep first 15 characters or each
                                         # line to exclude weekends. (5 weekdays *
                                         # 3 chars per day)
  
  lines = [line for line in lines if len(line.strip())] # Don't include empty lines
                                                        # happens if month starts
                                                        # on a weekend.
  
  # prints out the result
  print(title_line)
  for line in lines:
      print(line)
  
  # Next work out how many working days in month.
  nums = "".join(lines[1:]).split(" ") # Three parts: first lines[1:] means this
                                       # only looks at the portion of the calendar
                                       # with numbers written on then. 2nd "".join()
                                       # joins the lines into a single string on 1 line
                                       # 3rd the .split(" ") splits the string based on spaces
                                       # unfortunatly 2 consecutive spaces result in an empty
                                       # string.
  
  nums = [num for num in nums if len(num)] # Filters the empty string.
  print(f"There are {len(nums)} working days in the month you selected") # Prints result
  #(uses f-string, you may want to look them up, I find them to be very useful)
  

  回复于 2024-05-17T17:28:30+08:00
• 0

  检查日期工作日的一种方法是使用 date 对象的weekday()方法 . 它位于python标准库 datetime 模块中 .

  date.weekday（）以整数形式返回星期几，其中星期一为0，星期日为6.例如，日期（2002,12,4）.weekday（）== 2，星期三 . 另见isoweekday（） .

  import datetime
  
  num_of_weekdays = 0
  weekday_list = []
  
  start_date = datetime.date(int(input_year[0]), int(input_month[0]), 1)
  cur_date = start_date
  while cur_date.month == start_date.month:
      if 0 <= cur_date.weekday() <= 4:  # if it is a weekday
          num_of_weekdays += 1
          weekday_list.append(cur_date.day)
      cur_date += datetime.timedelta(days=1)
  
  print("The number of weekdays in ({}) of ({}) is ({}).".format(
      input_month[0], input_year[0], num_of_weekdays))
  
  date_ = datetime.date(int(input_year[0]), int(input_month[0]), int(input_date[0]))
  index = weekday_list.index(int(input_date[0])) + 1
  print("The ({}) is a ({}) and is the ({}) weekday of ({}), ({}).".format(
      date_.day, date_.strftime('%A'), index, date_.month, date_.year)
  

  回复于 2024-05-17T17:28:30+08:00
• 1

  要获得一个月中的工作日数量：

  import calendar
  
  weekdays = 0
  cal = calendar.Calendar()
  
  for week in cal.monthdayscalendar(2018, 7):
      for i, day in enumerate(week):
          # Check if is a weekday and the day is from this month
          if i < 5 and day != 0:
              weekdays += 1
  
  print weekdays
  

  要获取特定日期的工作日编号，您可以修改上述代码以在达到输入日时返回工作日计数 .

  回复于 2024-05-17T17:28:30+08:00