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从Python自动执行Dropbox OAuth身份验证

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对于我们使用Dropbox的全自动应用程序,我们需要使用'dropboxfs'(使用'pyfilesystem'的Dropbox FS层)自动登录Dropbox . 构造函数期望

https://github.com/btimby/fs-dropbox/blob/master/dropboxfs.py#L336

来自oauth进程的令牌密钥秘密 .

我们能以某种方式自动化oauth过程吗?我没有任何手动交互,其中应用程序使用oauth窗口启动浏览器,并且我必须确认oauth访问请求 .

app key secret不是问题 . 但我只是想为应用程序提供Dropbox用户名密码,以便直接访问Dropbox .

任何选择?

3 回答

  • 0

    我遇到了同样的挑战,我通过使用名为Splinter的Web应用程序的测试框架解决了这个问题 . 它允许我自动化浏览器操作 . 查看documentation页面 .

    这是我使用的代码:

    from splinter import *
    from dropbox import rest, session
    from dropbox import client as dbclient
    import time
    
    # Initiate Dropbox API
    APP_KEY = '###'
    APP_SECRET = '###'
    ACCESS_TYPE = 'dropbox'
    sess = session.DropboxSession(APP_KEY, APP_SECRET, ACCESS_TYPE)
    emailDropbox = '###'
    passwordDropbox = '###'
    
    request_token = sess.obtain_request_token()
    
    urlDropbox = sess.build_authorize_url(request_token)
    
    def phantomjsOAuth():
        # Target url
        print 'Target url: ', urlDropbox
    
        browser = Browser('phantomjs')
        print 'Starting phantomjs browser'
        print 'Visiting url'
        browser.visit(urlDropbox)
    
        # Email form
        print 'Is the email form present? ', browser.is_element_present_by_id('login_email')
        print 'Fill email form'
        browser.find_by_id('email-field').first.find_by_id('login_email').first.fill(emailDropbox)
        print 'Email form successfully filled'
    
        # Password form
        print 'Is the password form present? ', browser.is_element_present_by_id('login_password')
        print 'Fill password form'
        browser.find_by_id('login_password').first.fill(passwordDropbox)
        print 'Password form successfully filled'
    
        # Find login submit button
        print 'Is the "Submit" button present?', browser.is_element_present_by_name('login_submit_dummy')
        submitButton = browser.is_element_present_by_name('login_submit_dummy')
    
        if submitButton == True:
            print 'Pauzing for 5 seconds to avoid clicking errors'
            time.sleep(5)
            print 'Attempting to click the "Submit" button in order to login'
            browser.find_by_name('login_submit_dummy').first.click()
            print '"Submit" button successfully clicked'
    
            # Allow connection with Dropbox
            print 'Is the "Allow" button present?', browser.is_element_present_by_css('.freshbutton-blue')
            allowButton = browser.is_element_present_by_css('.freshbutton-blue')
    
            if allowButton == True:
                print 'The "Allow" button is present, attempting to click..'
                browser.find_by_css('.freshbutton-blue').click()
                print 'The "Allow" button is successfully clicked, access to Dropbox is granted.'
    
                dropboxCode()
    
            else:
                print 'The "Allow" button is not present, quitting.'
                browser.quit()
    
        else:
            print 'The "Submit" button was not present, quitting.'
            browser.quit()
    
    def dropboxCode():
        # The rest of the Dropbox code
        # This will fail if the user didn't visit the above URL and hit 'Allow'
        access_token = sess.obtain_access_token(request_token)
    
        client = dbclient.DropboxClient(sess)
        print "linked account:", client.account_info()
    
        f = open('working-draft.txt')
        response = client.put_file('/magnum-opus.txt', f)
        print "uploaded:", response
    
    phantomjsOAuth()
    
  • 1

    OAuth是Dropbox Core API提供的唯一身份验证,您无法使用用户名密码来获取访问权限 .

  • 0

    Dropbox API目前需要OAuth,这些条款禁止人们尝试自动化它的方式:

    https://www.dropbox.com/terms#acceptable_use https://www.dropbox.com/developers/reference/bestpractice

    (而且你真的不应该像那样存储你的用户名/密码 . )

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