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如果某些值，python循环再次？

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我正在尝试制作一个与用户一起播放“Rock Paper Scissors Lizard Spock”的程序 . 我已经完成了大部分工作，但我遇到的一个问题是如果游戏达到平局，我希望忽略这一结果，并重复循环 . 换句话说，我希望有三个输赢的结果 . 另外，为了完全搞砸我刚才所说的内容，我希望如果用户连续两次获胜或者程序连续两次获胜，它会完全退出循环 .

对于第一个问题，我尝试使用continue，但这根本不起作用 . 我在这个网站上经历过几个岩石剪刀问题，但我没有看到任何适用于此的答案 . 第一个问题具有优先权;第二个只是顶部的樱桃 .

这是我的代码（有点长，我很抱歉）：

import random
Rock = "Rock"
Paper = "Paper"
Scissors = "Scissors"
Lizard = "Lizard"
Spock = "Spock"
Words = (Rock, Paper, Scissors, Lizard, Spock)


def The_Game (x):
    for i in range(3):
        y = random.choice(Words)
        x = input("Choose your weapon! Rock, paper, scissors, lizard, or spock?")
        if x == y:
            print(y)
            print("Tie. Try again!")
        else:
            if x == Rock:
                if y == Paper:
                    print(y)
                    print("Paper covers Rock.  You lost this round!")
                elif (y == Spock):
                    print(y)
                    print("Spock vaporizes Rock. You lost this round!")
                elif (y == Lizard):
                    print(y)
                    print("Rock crushes Lizard. You won this round!")
                else:
                    print(y)
                    print("As always, Rock crushes Scissors.  You won this round!")
            elif (x == Paper):
                if y == Scissors:
                    print(y)
                    print("Scissors cut Paper.  You lost this round!")
                elif (y == Lizard):
                    print(y)
                    print("Lizard eats paper.  You lost this round!")
                elif (y == Rock):
                    print(y)
                    print("Paper covers Rock.  You won this round!")
                else:
                    print(y)
                    print("Paper disproves Spock.  You won this round!")
            elif (x == Scissors):
                if y == Rock:
                    print(y)
                    print("As always, Rock crushes Scissors.  You lost this round!")
                elif (y == Spock):
                    print(y)
                    print("Spock melts scissors.  You lost this round!")
                elif (y == Paper):
                    print(y)
                    print("Scissors cut Paper.  You won this round!")
                else:
                    print(y)
                    print("Scissors decapitate Lizard.  You won this round!")
            elif (x == Lizard):
                if y == Rock:
                    print(y)
                    print("Rock crushes Lizard. You lost this round!")
                elif (y == Scissors):
                    print(y)
                    print("Scissors decapitate Lizard.  You lost this round!")
                elif (y == Paper):
                    print(y)
                    print("Lizard eats Paper.  You won this round!")
                elif (y == Spock):
                    print(y)
                    print("Lizard poisons Spock.  You won this round!")
            else:
                if y == Paper:
                    print(y)
                    print("Paper disproves Spock.  You lost this round!")
                elif (y == Lizard):
                    print(y)
                    print("Lizard poisons Spock.  You lost this round!")
                elif (y == Scissors):
                    print(y)
                    print("Spock melts scissors.  You won this round!")
                else:
                    print(y)
                    print("Spock vaporizes Rock. You won this round!")


x = ("Let's play Rock Paper Scissors Lizard Spock!  Best 2 of three!")
print(x)
The_Game(x)

Yes = "Yes"
No = "No"
p = input("Play again? (Yes or No)  ")
    if p == Yes:
        The_Game(x)
    else:
        print("Thanks for playing!")

如果有人可以提供帮助，那就太好了！我只是python的初学者 .

python loops

1 回答

  • 0

    好的，我们先稍微改变你的代码 . 我没有玩过3次，而是让它玩一次 .

    然后，一旦我们完成了这个，我们就可以使每次调用 TheGame() 都有一个有用的返回值 . 如果用户赢了，那么回归的一个有用 Value 就是 . 提出这个的一种方法是，如果玩家获胜，则执行 return True ，否则执行 return False .

    例如：

    if x == Rock and y == Paper:
    print(y)
    print("Paper covers Rock.  You lost this round!")
    return False

    然后，你的主循环可能会变成这样：

    print("Let's play Rock Paper Scissors Lizard Spock!  Best 2 of three!")

win_count = 0
loss_count = 0
while win_count < 2 and loss_count < 2:
    if The_Game(x) == True:
        win_count = win_count + 1
    else:
        loss_count = loss_count + 1

if win_count == 2:
    print("You won the set!")
else:
    print("You lost the set!")

    注意：您可能想要检查用户的输入是否在您想要的范围内 . 您可以使用条件检查： if x not in Words:

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