首页 文章

在Modelica中正确使用inStream（）

提问于
浏览 次
3

我正在尝试在Modelica中构建一个非常简单的分布式热流体体积模型，并且正在努力使用流操作符正确实现它 . 本卷使用DryAirNasa作为媒介，我希望它没有大容量存储，没有压降，也没有能量存储（很像Modelica.Fluid.Pipes.StaticPipe模型） . 但是，我想明确地执行能量 balancer ，以便可以进行热传递 . 我也不希望在这个模型中定义质量流量，而是在连接到管道末端的一个边界中定义它（例如，Modelica.Fluid.Sources.MassFlowSource_h） .

我已经创建了这种模型的测试实现，但是根据Dymola，这个模型显然没有一个方程式 . 我很感激有关如何修复此模型的任何见解，以便它是正确的 . 如果我加上等式

port_a.h_outflow = Medium.specificEnthalpy(state_a)

对于方程部分，模型具有相同数量的方程和未知数，但我没有任何有理由添加这样的方程 .

model AirFlowTemp

  // Objective: create a component that has no pressure drop, no mass storage,
   and no energy storage, but that has a heat input.

  import SI=Modelica.SIunits;

  final replaceable package Medium=Modelica.Media.Air.DryAirNasa;

  AirFlow.AirFlowPort port_a(redeclare package Medium
      = Medium);
  AirFlow.AirFlowPort port_b(redeclare package Medium
      = Medium);
  Interfaces.HeatPort heatPort;

  Medium.EnthalpyFlowRate[2] H_flow "enthalpy flow";
  SI.HeatFlowRate Q_flow "heat flow rate";

  Medium.Temperature T_mean;
  Medium.ThermodynamicState state_a;
  Medium.ThermodynamicState state_b;

equation 
  // no pressure drop across the component.
  port_a.p = port_b.p;

  // Assume that there is no mass storage in the volume
  0 = port_a.m_flow + port_b.m_flow;

  // Energy balance
  H_flow[1] = semiLinear(port_a.m_flow, inStream(port_a.h_outflow), inStream(port_b.h_outflow));
  H_flow[2] = semiLinear(port_b.m_flow, inStream(port_b.h_outflow), inStream(port_a.h_outflow));
  0 = Q_flow + H_flow[1] + H_flow[2];

  state_a = Medium.setState_ph(port_a.p, inStream(port_a.h_outflow));
  state_b = Medium.setState_ph(port_b.p, inStream(port_b.h_outflow));

  T_mean = (Medium.temperature(state_a) +
            Medium.temperature(state_b))/2;

  heatPort.Q_flow = Q_flow;
  heatPort.T = T_mean;

end AirFlowTemp;

connector AirFlowPort

  replaceable package Medium = Modelica.Media.Interfaces.PartialMedium;

  Medium.AbsolutePressure p;
  flow Medium.MassFlowRate m_flow;
  stream Medium.SpecificEnthalpy h_outflow;
  stream Medium.MassFraction Xi_outflow[Medium.nXi];

end AirFlowPort;


connector HeatPort
  extends Modelica.Thermal.HeatTransfer.Interfaces.HeatPort;
end HeatPort;
modelica

1 回答

  • 0

    大约4个星期前，我遇到了同样的问题 . 尝试将其作为接近正确使用inStream的步骤 .

    • 删除Medium.EnthalpyFlowRate [2] H_flow“焓流”SI.HeatFlowRate Q_flow“热流率”; Interfaces.HeatPort heatPort; SI.HeatFlowRate Q_flow“热流率”; Medium.Temperature T_mean; T_mean =（Medium.temperature（state_a）Medium.temperature（state_b））/ 2;

    heatPort.Q_flow = Q_flow; heatPort.T = T_mean; =>只测试管道，没有heatPort

    • 使用port_a.outflow * port_a.m_flow = inStream（port_b.outflow）* port_b.m_flow; port_b.outflow * port_b.m_flow = inStream（port_a.outflow）* port_a.m_flow;

    而不是：H_flow [1] = semiLinear（port_a.m_flow，inStream（port_a.h_outflow），inStream（port_b.h_outflow））; H_flow [2] = semiLinear（port_b.m_flow，inStream（port_b.h_outflow），inStream（port_a.h_outflow））; 0 = Q_flow H_flow [1] H_flow [2];

    • 更改您的测试没有热量运动

    =>这有用吗？

    关心Uwe

    回复于

相关问题