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如何将表单传递给基于类的通用视图（TodayArchiveView）？

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url.py

from django.conf.urls import patterns, include, url
import os.path
from crm.views import *

urlpatterns += patterns('',
    (r'^test/$', tView.as_view()),
)

views.py

from django.views.generic import TodayArchiveView
from crm.forms import *
from crm.models import *

class tView(TodayArchiveView):
    model = WorkDailyRecord
    context_object_name = 'workDailyRecord'
    date_field = 'date'
    month_format = '%m'
    template_name = "onlyWorkDailyRecord.html"
    form_class = WorkDailyRecordForm ################## ADD

tView是通用视图.... WorkDailyRecord是在models.py中定义模型

我想将表单（forms.py中的'WorkDailyRecordForm'类）传递给模板（onlyWorkDailyRecord.html）

怎么样？？

加

forms.py

from django import forms

class WorkDailyRecordForm(forms.Form):
    contents = forms.CharField(label='',
            widget=forms.Textarea(attrs={'placeholder': 'contents', 'style':'width:764px; height:35px;'}),
            required=False,
        )
    target_user = forms.CharField(label='',
            widget=forms.TextInput(attrs={'placeholder': 'target', 'style':'width:724px'}),
            required=False,
        )

onlyWorkDailyRecord.html

<form method="post" action="." class="form-inline" id="save-form">
    {{ form.as_table }}
    <button type="submit" class="btn btn-mini" id="workDailyRecord-add">작성</button>
</form>
python django python-2.7 django-generic-views django-1.4

1 回答

  • 0

    在基于类的视图中，您需要提及 form_class ：

    form_class = WorkDailyRecordForm

    一个简单的例子：

    class tView(TodayArchiveView):
    form_class = WorkDailyRecordForm
    template_name = 'onlyWorkDailyRecord.html'
    model = WorkDailyRecord

    def form_valid(self, form, **kwargs):
        instance = form.save(commit=True)
        return HttpResponse('Done')

    def dispatch(self, request, *args, **kwargs):
        return super(tView, self).dispatch(request, *args, **kwargs)

    有关更多信息，请阅读generic-editing in class based views

    回复于

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