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Danjgo：CharField不支持查找'case_exact'或不允许在该字段上加入

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这是我的服务器上的GET请求 .

HTTP GET /testPage/?persona_name=Aman&key_name=country&key_label=My+Country&key_value=India&Save=Submit 500

在这个视图的帮助下，我从GET请求中获取值 .

def PersonaSave(request):
    persona_name = request.GET.get('persona_name',)
    persona_key = request.GET.get('key_name',)
    persona_key_value = request.GET.get('key_value',)
    persona_key_label = request.GET.get('key_label',)
    persona_submit = request.GET.get('Save',)
    return( persona_name , persona_key , persona_key_label , persona_key_value , persona_submit

以下是我正在检查具有给定角色名称的对象是否存在的函数 . 如果它存在，那么我正在更新值，如果它是一个新的角色，那么我正在制作新的testPersona对象 .

def TestPageView(request):
    x=PersonaSave(request)
    persona_name = x[0]
    persona_key = x[1]
    persona_key_label=x[2]
    persona_key_value=x[3]
    persona_submit=x[4]
    testPersonaName = TestPersonaName(name=persona_name)
    testPersonaName.save()

    if(persona_name is None and persona_key is None and persona_key_label is None and persona_key_value is None):
        return render(request, 'dashboard/test_page.html')

 # Below is the function for updating testPersona . 

    elif TestPersonaName.objects.filter(name__case_exact=persona_name).exists():
        testpersona = TestPersona.objects.get(name__case_exact=persona_name)
        if testpersona.key == persona_key:
            testpersona.label= persona_key_label
            testpersona.value = persona_key_value
            testpersona.save()




#If persona with new name is detected then saving a new testPersona object.
      testpersona=TestPersona(name=persona_name,key=persona_key,label=persona_key_label,value=persona_key_value)
        testpersona.save()

        return render(request,'dashboard/test_page.html')

Following is the error that i am getting.

django.core.exceptions.FieldError: Unsupported lookup 'case_exact' for CharField or join on the field not permitted.

Below are TestPersona and TestPersonaName models.

    class TestPersonaName(models.Model):
        name = models.CharField(max_length=100,null=True)
        def __str__(self):
            return self.name

    class TestPersona(models.Model):
        name = models.ForeignKey('TestPersonaName',null=True)
        key  = models.CharField(max_length=200,null=True,blank=True)
        label = models.CharField(max_length=200,null=True,blank=True)
        value = models.CharField(max_length=200,null=True,blank=True)
        def __str__(self):
            return self.name + " " + self.key

请您解释一下为什么我收到此错误，如何删除此错误？提前致谢 .

python django django-views

3 回答

  • 0

    您应该在确切字段名称和模型字段名称之间使用 2 underscores .

    假设您正在匹配名为 persona_name 的字段

    elif TestPersonaName.objects.filter(persona_name__iexact=persona_name).exists():
    testpersona = TestPersona.objects.get(persona_name__iexact=persona_name)

    iexact 匹配值，无论区分大小写 .

    回复于
  • 1

    改变这一行

    testpersona = TestPersona.objects.get(name__case_exact=persona_name)

    至

    testpersona = TestPersona.objects.get(name__name__case_exact=persona_name)
    回复于
  • 1

    最后，在这个问题上花了一整天后，我能够知道我在哪里做错了 .

    在TestPersona模型中，有一个字段'name'，它是建模TestPersonaName的外键 . 这意味着TestPersonaName的对象将被分配到TestPersona的'name'字段 . 所以答案是：

    def TestPageView(request):
    x=PersonaSave(request)
    persona_name = x[0]
    persona_key = x[1]
    persona_key_label=x[2]
    persona_key_value=x[3]
    persona_submit=x[4]

    if(persona_name is None and persona_key is None and persona_key_label is None and persona_key_value is None):

    # Since no paramteres are persent in GET request(i.e Nothing is filled in form), then we will simply render the blank form.
        return render(request, 'dashboard/test_page.html')

 #  Below is the function for updating testPersona . 

    elif TestPersonaName.objects.filter(name__iexact=persona_name).exists():
        testPersonaName_obj = TestPersonaName.objects.filter(name__iexact=persona_name) #Fetching an object from TestPersonaName model where name = persona_name
        testpersonaSet = TestPersona.objects.filter(name=testPersonaName_obj) #Passing testPersonaName_obj to 'name' field of TestPersona model because name is foreign key.
        for testpersona in testPersonaSet: #testPersonaSet is a QuerySet
            if testpersona.key == persona_key: #Checking whether persona with given key is already present or not

         # If TestPersona object with given name and give key is already present then we will update the details instead of making a new object.
                testpersona.label= persona_key_label 
                testpersona.value = persona_key_value
                testpersona.save()
                return render(request,'dashboard/test_page.html')    

#If persona with new name is detected then saving new objects of TestPersonaName and TestPersona object.
    testPersonaName = TestPersonaName(name=persona_name)
    testPersonaName.save() 
    testpersona(name=testPersonaName,key=persona_key,label=persona_key_label
                ,value=persona_key_value)
    testpersona.save()
    return render(request,'dashboard/test_page.html')
    回复于

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