public class Foo { }
class Program
{
static void Main()
{
var foo = new Foo();
var serializer = new XmlSerializer(foo.GetType());
var ns = new XmlSerializerNamespaces();
ns.Add(string.Empty, string.Empty);
serializer.Serialize(Console.Out, foo, ns);
}
}
1 回答
通过使用Serialize方法:
注意最后一个参数(
ns
) .