当我尝试运行600个测试的智能卡测试工具的主机程序时,我不断收到此错误“RuntimeError:调用Python对象时超出了最大递归深度”,我在第300次测试后得到此错误,我尝试了“sys.setrecursionlimit( 10000)“并解决了这个问题,但我知道这不是解决这个错误的最佳方法,我怎么能改变我的代码所以我不会遇到这个错误:
def SndRcv(self,request):
print ">> ", request
device_api.send(request)
resp = device_api.receive()
print "<< ", resp
self.processResponse(resp)
def processResponse(self, K400Message):
global mWaitingCardRemoval
ciMsg = card_interface_response
ciMsgType = card_interface_response.ci_msg
if ciMsgType is None:
print 'weird, malformed protobuf response'
return
whichMsg = ciMsgType.WhichOneof('msg')
print 'msg = ' + str(whichMsg)
if whichMsg is 'collision':
self.StartSession()
elif whichMsg is 'card_removed':
if ciMsgType.issuer== ci.CARD_INTERFACE_MASK_CxLESS:
mWaitingCardRemoval &= ~(ciMsgType.issuer)
if EndofSession is False:
self.parseMessage()
if mWaitingCardRemoval !=0:
self.parseMessage()
self.StartSession()
elif whichMsg is 'waiting_removal':
if EndofSession is False:
self.parseMessage()
else:
mWaitingCardRemoval |= ciMsgType.issuer
elif whichMsg is 'card_detected':
mode = ciMsgType.issuer
reqMsg = pm.get_Deactivate((ci.CARD_INTERFACE_MASK_ANY)& ~(ciMsgType.issuer))
self.SendOnly(reqMsg)
acceptMsg = pm.get_Activate(mode)
self.SndRcv(acceptMsg)
elif whichMsg is 'card_ready':
self.StartLoop(ciMsgType.issuer)
elif whichMsg is 'rapdu':
self.processCardAPDUResponse(ciMsgType.issuer, ciMsg.data.encode('hex'))
elif whichMsg is 'card_not_responding':
if ciMsgType.issuer == ci.CARD_INTERFACE_MASK_CONTACT:
self.EndCardSession(ciMsgType.issuer,True)
else:
self.EndCardSession(ciMsgType.issuer, False)
elif whichMsg is 'resp_special':
if ciMsg.data.encode('hex') > 0:
logging.info(ciMsg.data.encode('hex'))
else:
logging.info("")
1 回答
您使用递归来编写一个固有的迭代过程 . 你_12404487_踩过一系列输入 . 处理完输入并报告响应后,您就完成了它 . 在调用堆栈上有's no reason to keep it'的上下文 . 当您点击最终测试并通过您的千多次调用返回时,您不会对结果或函数状态执行任何操作以返回到主程序 .
将其重写为简单的迭代 . 你是怎么开始的?你如何从一个测试进展到另一个测试?你怎么知道什么时候你的最外面的循环很可能依赖于一个简单的 while :
那会让你感动吗?