我在图像上使用 otsu threshold
.
这是输入图像:
这是输出:
这是我正在使用的代码:
#include "opencv2/imgproc/imgproc.hpp"
#include "opencv2/highgui/highgui.hpp"
#include <stdlib.h>
#include <stdio.h>
#include <iostream>
#include <string>
#include <math.h>
using namespace std;
using namespace cv;
int main(int argc, char const *argv[]) {
title("Text Extractor");
string win_name = "textextractor";
Mat img_a;
img_a = imread("../input/test_c.jpg");
Mat img_a_gray;
cvtColor(img_a, img_a_gray, CV_BGR2GRAY);
Mat img_a_blur;
GaussianBlur(img_a_gray, img_a_blur, Size(3, 3), 0, 0);
Mat img_a_thres;
// adaptiveThreshold(img_a_blur, img_a_thres, 255, ADAPTIVE_THRESH_MEAN_C, THRESH_BINARY, 5, 4);
threshold(img_a_blur, img_a_thres, 0, 255, THRESH_OTSU);
namedWindow(win_name + "_a", CV_WINDOW_AUTOSIZE);
imshow(win_name + "_a", img_a_thres);
imwrite("../output/output_a.jpg", img_a_thres);
waitKey(0);
return 0;
}
问题是输出在底部和左侧有一个黑色区域 . 我该怎么做才能最小化/删除它?
编辑:
我试过 equalizeHist()
,我得到了这个:
将尝试将图像分解成碎片并单独处理它们 .
对不起这是我的错 . 前一个是使用自适应过滤 . 使用 Otsu
我得到这个:
otsu的输出没有变化:/
编辑2:完成了Feng Tan算法,它提供了更好的结果,但是文本没有清晰度 .
码:
#include "opencv2/imgproc/imgproc.hpp"
#include "opencv2/highgui/highgui.hpp"
#include "opencv2/photo/photo.hpp"
#include <stdlib.h>
#include <stdio.h>
#include <iostream>
#include <string>
#include <math.h>
using namespace std;
using namespace cv;
int main(int argc, char const *argv[]) {
string win_name = "textextractor";
Mat img_c;
img_c = imread("../input/sample.jpg");
Mat img_c_gray;
cvtColor(img_c, img_c_gray, CV_BGR2GRAY);
Mat img_c_bin = Mat::zeros(img_c_gray.rows, img_c_gray.cols, CV_8UC1);
int s_win = 17;
int l_win = 35;
double min_tau = 10;
Rect roi_s = Rect(-s_win/2, -s_win/2, s_win, s_win);
Rect roi_l = Rect(-l_win/2, -l_win/2, l_win, l_win);
Rect img_c_roi = Rect(0, 0, img_c_gray.cols, img_c_gray.rows);
for (size_t r = 0; r < img_c_gray.rows; r++) {
for (size_t c = 0; c < img_c_gray.cols; c++) {
double pthres = 255;
Rect sROI = roi_s + Point(c, r);
sROI = sROI & img_c_roi;
if(sROI.width == 0 || sROI.height == 0) {
continue;
}
Rect lROI = roi_l + Point(c, r);
lROI = lROI & img_c_roi;
if(lROI.width == 0 || lROI.height == 0) {
continue;
}
Mat sROI_gray = img_c_gray(sROI);
Mat lROI_gray = img_c_gray(lROI);
double s_stdDev = 0;
double l_stdDev = 0;
double s_mean = 0;
double l_mean = 0;
double l_min = DBL_MAX;
for (size_t r = 0; r < sROI_gray.rows; r++) {
for (size_t c = 0; c < sROI_gray.cols; c++) {
s_mean += sROI_gray.at<unsigned char>(r, c);
}
}
s_mean = s_mean / static_cast<double> (sROI_gray.cols * sROI_gray.rows);
for (size_t r = 0; r < sROI_gray.rows; r++) {
for (size_t c = 0; c < sROI_gray.cols; c++) {
double diff = sROI_gray.at<unsigned char> (r, c) - s_mean;
s_stdDev += diff * diff;
}
}
s_stdDev = sqrt(s_stdDev / static_cast<int> (sROI_gray.cols * sROI_gray.rows));
for (size_t r = 0; r < lROI_gray.rows; r++) {
for (size_t c = 0; c < lROI_gray.cols; c++) {
l_mean += lROI_gray.at<unsigned char> (c, r);
if(lROI_gray.at<unsigned char> (r, c) < l_min) {
l_min = lROI_gray.at<unsigned char> (r, c);
}
}
}
l_mean = l_mean / static_cast<double> (lROI_gray.cols * lROI_gray.rows);
for (size_t r = 0; r < lROI_gray.rows; r++) {
for (size_t c = 0; c < lROI_gray.cols; c++) {
double diff = lROI_gray.at<unsigned char> (r, c) - l_mean;
l_stdDev += diff * diff;
}
}
l_stdDev = sqrt(l_stdDev / static_cast<double> (lROI_gray.cols * lROI_gray.rows));
double tau = ((s_mean - l_min) * (1 - s_stdDev / l_stdDev)) / 2.0;
if(tau < min_tau) {
tau = min_tau;
}
double threshold = s_mean - tau;
unsigned char pixel_val = img_c_gray.at<unsigned char>(r, c);
if(pixel_val >= threshold) {
img_c_bin.at<unsigned char> (r, c) = 255;
} else {
img_c_bin.at<unsigned char> (r, c) = 0;
}
}
}
namedWindow(win_name + "_c", CV_WINDOW_AUTOSIZE);
imshow(win_name + "_c", img_c_bin);
imwrite("../output/output_c.jpg", img_c_bin);
waitKey(0);
return 0;
}
输出:
2 回答
这是我在一些试验和运行后能够获得的 . 最初我 median blurred 原始图像 . 然后我将 adpative threshold 应用于模糊图像 .
这就是我得到的:
1. Adaptive Threshold using Gaussian filter:
2. Adaptive Threshold using Mean filter:
从这里开始,您可以执行一系列最适合您最终图像的形态学操作 . :)
你应该尝试使用CLAHE .
我在MATLAB上尝试使用:
结果:
注意:您可以对此图像应用阈值处理 . 大津现在应该工作正常 .