我试着找到答案,但没有看到一个针对我的特定问题 . 我正在使用三元搜索树的共享指针(用于预测文本算法),并使用共享指针遇到一些问题 .
我离开C已经5年了,让我告诉你,Java并没有帮助你学习指针 . 我不得不重新学习在过去几天里我在学校学到的指针材料,并成功设法破坏了我的代码 .
这是我的大部分代码:
// TernarySearchTree.cc
#include "stdafx.h"
#include "ternary_search_tree.h"
//Constructor
TernarySearchTree::TernarySearchTree() {
num_nodes_ = 0;
size_in_memory_ = 0;
root_node_ = nullptr;
}
TernarySearchTree::TernarySearchTree(const TernarySearchTree& other) {
num_nodes_ = other.num_nodes_;
size_in_memory_ = other.size_in_memory_;
TernarySearchTreeNode node;
node = *other.root_node_;
root_node_.reset(&node);
}
//Destructor
TernarySearchTree::~TernarySearchTree() {
}
//operators
TernarySearchTree& TernarySearchTree::operator=(const TernarySearchTree& other) {
//TODO: swap idiom - create a copy of the node then swap the new one with it
//do this first to provide exception safety
TernarySearchTreeNode node;
node = *other.root_node_;
root_node_.reset(&node);
num_nodes_ = other.num_nodes_;
size_in_memory_ = other.size_in_memory_;
return *this;
}
//Convert from string to c-style string
std::vector<char> TernarySearchTree::ConvertStringToCString(std::string str) {
std::vector<char> wordCharacters (str.begin(), str.end());
//remove newlines or tabs
if (wordCharacters.back() == '\n' || wordCharacters.back() == '\t') {
wordCharacters.pop_back();
}
wordCharacters.push_back('\0');
return wordCharacters;
}
//Insert a node
TernarySearchTreeNode TernarySearchTree::InsertNode(TernarySearchTreeNode ¤tNode,
char character,
NodePosition position,
bool isRoot) {
TernarySearchTreeNode newNode;
newNode.set_character(character);
if (!isRoot) {
switch (position) {
case NODE_POS_LEFT:
currentNode.set_left_node(newNode);
break;
case NODE_POS_CENTRE:
currentNode.set_centre_node(newNode);
break;
case NODE_POS_RIGHT:
currentNode.set_right_node(newNode);
break;
default:
break;
}
}
return newNode;
}
//Insert a word
void TernarySearchTree::InsertWord(std::string word) {
std::vector<char> characters = ConvertStringToCString(word);
std::shared_ptr<TernarySearchTreeNode> currentNode = 0;
bool isFirstCharacter = true;
//Add each character to a node while traversing
//Base case where there is no root node
if (!root_node_) {
for(std::vector<char>::iterator it = characters.begin(); it != characters.end(); ++it) {
if (*it != '\0') {
//if it is the first character
//root_node_ is equal to the address of new node
if (isFirstCharacter) {
std::cout << "HIHI";
TernarySearchTreeNode node = InsertNode(*currentNode, *it, NODE_POS_CENTRE, true);
root_node_.reset(&node);
currentNode.reset(&node);
isFirstCharacter = false;
} else {
TernarySearchTreeNode node = InsertNode(*currentNode, *it, NODE_POS_CENTRE, false);
std::cout << std::endl << node.get_character();
currentNode.reset(&node);
}
}
}
//If not base case, then we need to compare each character
} else {
currentNode = root_node_;
for(std::vector<char>::iterator it = characters.begin(); it != characters.end(); ++it) {
if (*it != '\0') {
currentNode.reset(&SetNextNode(*currentNode, *it, *std::next(it, 1)));
} else {
currentNode->set_end_of_word(true);
}
}
}
}
//Recursive function for obtaining/adding the next node when inserting a word
TernarySearchTreeNode TernarySearchTree::SetNextNode(TernarySearchTreeNode ¤tNode, const char currentChar, const char nextChar) {
//If characters match
if (currentChar == currentNode.get_character()) {
//if centre node exists
if (currentNode.get_centre_node()) {
return *(currentNode.get_centre_node());
//Otherwise, create a new node and recall method on that node
} else {
//If not the end of the word, make a new node with the next letter
if (nextChar != '\0') {
return InsertNode(currentNode, nextChar, NODE_POS_CENTRE, false);
} else {
return currentNode;
}
}
//If it is less, follow node on the left
} else if (currentChar < currentNode.get_character()) {
//if left node exists, recursive call
if (currentNode.get_left_node()) {
return SetNextNode(*(currentNode.get_left_node()), currentChar, nextChar);
//Otherwise, create a new node and recall method on that node
} else {
return SetNextNode(InsertNode(currentNode, currentChar, NODE_POS_LEFT, false), currentChar, nextChar);
}
//Otherwise it is bigger, so take right path
} else {
//if right node exists, recursive call
if (currentNode.get_right_node()) {
return SetNextNode(*(currentNode.get_right_node()), currentChar, nextChar);
//Otherwise, create a new node and recall method on that node
} else {
return SetNextNode(InsertNode(currentNode, currentChar, NODE_POS_RIGHT, false), currentChar, nextChar);
}
}
}
//Populate the TST from a word list/file
void TernarySearchTree::PopulateTreeFromTextFile(std::string fileName) {
std::ifstream file;
std::string line;
file.open(fileName);
if (file.is_open()) {
//Assume text file has one word per line
while (std::getline(file, line)) {
InsertWord(line);
}
}
}
//Search
bool TernarySearchTree::SearchForWord(std::string word) {
return false;
}
int _tmain(int argc, _TCHAR* argv[])
{
//Test
TernarySearchTree tst;
//Open file
tst.PopulateTreeFromTextFile("simple.txt");
//start at root and follow some paths
std::cout << tst.get_root_node();
/**std::vector<char> vec;
vec.push_back('a');
vec.push_back('c');
std::vector<char>::iterator it = vec.begin();
std::cout << *std::next(vec.begin(), 1);
std::cout << (*it < 'c');
it++;
std::cout << *std::next(it, 0);
std::cout << (*it < 'c');
**/
return 0;
}
并为节点:
/*TST node methods */
#include <iostream>
#include "ternary_search_tree_node.h"
/** ADD COPY CONSTRUCTOR*/
//Constructors
TernarySearchTreeNode::TernarySearchTreeNode() {
character_ = '\0';
end_of_word_ = false;
left_node_ = nullptr;
centre_node_ = nullptr;
right_node_ = nullptr;
}
TernarySearchTreeNode::TernarySearchTreeNode(const TernarySearchTreeNode& other) {
character_ = other.character_;
end_of_word_ = other.end_of_word_;
TernarySearchTreeNode leftNode;
leftNode = *other.left_node_;
left_node_.reset(&leftNode);
TernarySearchTreeNode centreNode;
centreNode = *other.centre_node_;
centre_node_.reset(¢reNode);
TernarySearchTreeNode rightNode;
rightNode = *other.right_node_;
right_node_.reset(&rightNode);
}
TernarySearchTreeNode::TernarySearchTreeNode(char character, bool end_of_word,
TernarySearchTreeNode left_node,
TernarySearchTreeNode centre_node,
TernarySearchTreeNode right_node) {
character_ = character;
end_of_word_ = end_of_word;
left_node_.reset(&left_node);
centre_node_.reset(¢re_node);
right_node_.reset(&right_node);
}
//Destructor
TernarySearchTreeNode::~TernarySearchTreeNode() {
left_node_.reset();
centre_node_.reset();
right_node_.reset();
}
//operators
TernarySearchTreeNode& TernarySearchTreeNode::operator=(const TernarySearchTreeNode& other) {
if (&other) {
TernarySearchTreeNode leftNode;
leftNode = *other.left_node_;
TernarySearchTreeNode centreNode;
centreNode = *other.centre_node_;
TernarySearchTreeNode rightNode;
rightNode = *other.right_node_;
left_node_.reset(&leftNode);
centre_node_.reset(¢reNode);
right_node_.reset(&rightNode);
character_ = other.character_;
end_of_word_ = other.end_of_word_;
}
return *this;
}
//printing
std::ostream& operator<<(std::ostream& os, const TernarySearchTreeNode& obj)
{
// write obj to stream
char c = obj.get_character();
bool b = obj.is_end_of_word();
os << c << "\t is end of word: " << b;
return os;
}
当我在调试模式(Visual Studios)中运行时,它能够设置根节点,但是当它输入第二个节点时,当currentNode在函数的else语句中调用.reset(&node)时,它崩溃尝试删除"stuff" InsertWord . 我在复制构造函数或operator =方法或析构函数中做错了吗?它上方的cout行确实打印了正确的字母,因此看起来节点正在正确创建 .
调试调用堆栈显示:
TernarySearchTree.exe!std :: _ Ref_count_base :: _ Decref()Line 118 C TernarySearchTree.exe!std :: _ Ptr_base :: _ Decref()Line 347 C TernarySearchTree.exe!std :: shared_ptr :: ~shared_ptr()Line 624 C TernarySearchTree.exe!std :: shared_ptr :: reset()行649 C TernarySearchTree.exe!TernarySearchTreeNode ::〜TernarySearchTreeNode()第50行C TernarySearchTree.exe!TernarySearchTreeNode ::`标量删除析构函数'(unsigned int)C TernarySearchTree.exe !std :: _ Ref_count :: _ Destroy()行161 C TernarySearchTree.exe!std :: _ Ref_count_base :: _ Decref()行120 C TernarySearchTree.exe!std :: _ Ptr_base :: _ Decref()行347 C TernarySearchTree.exe!std :: shared_ptr :: ~shared_ptr()第624行第3行TernarySearchTree.exe!std :: shared_ptr :: reset()行649 C TernarySearchTree.exe!TernarySearchTreeNode :: ~TernarySearchTreeNode()第50行C TernarySearchTree.exe!TernarySearchTree :: InsertWord (std :: basic_string,std :: allocator word)第105行C TernarySearchTree.exe!TernarySearchTree :: PopulateTreeFromTextFile(s td :: basic_string,std :: allocator fileName)行182 C TernarySearchTree.exe!wmain(int argc,wchar_t * * argv)行200 C TernarySearchTree.exe!__ tmainCRTStartup()行533 C TernarySearchTree.exe!wmainCRTStartup()行377 C kernel32.dll!7592338a()未知[下面的框架可能不正确和/或缺少,没有为kernel32.dll加载符号] ntdll.dll!77599f72()未知ntdll.dll!77599f45()未知
感谢您的任何帮助,您可以提供!如果有任何其他你需要我提供的话,请告诉我(我正在阅读的文本文件中只有单词 corn
) .
1 回答
您的问题是您在C中使用Java样式 . 与Java中的所有内容本质上都是指针不同,在C中,您必须考虑值,引用,指针和对象生存期之间的差异 .
这个功能不好:
您按值获取
TernarySearchTreeNode
个对象,然后将其地址放入shared_ptr
.shared_ptr
to获取动态分配对象(使用new
创建的对象)的所有权,并在引用计数变为零时删除它 . 上面的对象(left_node等)是堆栈对象,它们将在函数末尾超出范围 . 当您将其地址放入shared_ptr
时,它将稍后尝试删除这些对象,但它们不再存在 .至于建议如何解决这个问题,这里有很多假设刚刚结束 . 例如,子节点可以有多个父节点吗?复制节点真的有意义吗?
我现在假设复制节点是有意义的,所以使用
shared_ptr
是合理的 . 那样的话我们可以从这里开始:然后像
set_left_node
这样的所有函数也应该将std::shared_ptr<TernarySearchNode>
作为参数 . 您不应该调用reset()
,它允许shared_ptr
获取空闲指针的所有权(refcount == 1) .shared_ptr
通过在析构函数中增加复制和解除引用的引用计数来工作 . 当您取消引用指针然后获取地址时,您正在使用shared_ptr .