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Python TCP服务器接受新套接字,但从不接收数据

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我已经走到了尽头 - 我无法想象这一点 . 我是Python的新手,我正在编写一个TCP服务器/客户端应用程序 .

服务器侦听连接并生成线程以处理连接 . 通信非常简单 - 客户端 Build 连接,发送消息,服务器响应然后关闭连接(ala HTTP)

问题是我的服务器代码不能始终从客户端接收任何数据 . 服务器接受新连接,旋转新线程,然后阻止.recv方法 .

Server Listener

class TCPListener(threading.Thread):

    def __init__(self, ip = settings.BIND_IP, port = settings.BIND_PORT):
        super(TCPListener, self).__init__()
        self.daemon = True
        self._port = port
        self._ip = ip
        self.stop = threading.Event()
        self.stop.clear()

        self.tcp_server_socket = socket(AF_INET, SOCK_STREAM)
        self.tcp_server_socket.setsockopt(SOL_SOCKET, SO_REUSEADDR, 1)
        self.tcp_server_socket.setblocking(False)
        self.tcp_server_socket.bind((self._ip, self._port))

    def run(self):
        # Listen for client connection requests
        with lock:
            utils.log_message("Listening for ledger messages on port {0}".format(self._port))

        try:
            self.tcp_server_socket.listen(5)

            # List for managing spawned threads
            socket_threads = []

            # Non-blocking socket loop that can be interrupted with a signal/event
            while True and not self.stop.is_set():
                try:
                    client_socket, address = self.tcp_server_socket.accept()

                    # Spawn thread
                    client_thread = TCPConnectionThread(client_socket)
                    client_thread.start()
                    socket_threads.append(client_thread)

                except Exception as e:
                    continue

            # Clean up all the threads
            for thread in socket_threads:
                thread.join()

        except Exception as e:
            print("Could not bind to port: {0}".format(e))
        finally:
            self.tcp_server_socket.close()

Server Connection Handler

class TCPConnectionThread(threading.Thread):

    def __init__(self, socket):
        super(TCPConnectionThread, self).__init__()
        with lock:
            utils.log_message("Spawning TCP Connection Thread from {0}".format(socket.getsockname()))
        self._socket = socket


    def run(self): 
        # Get message
        message = ''
        data = True
        while data:
            data = self._socket.recv(4096)  #BLOCKS HERE 99% OF THE TIME
            message+=data.decode()

        with lock:
            utils.log_message("Received message from {0}:\n{1}".format(self._socket.getsockname(), message))

        self._socket.sendall(response)
        self._socket.close()

从我的客户端处理连接的线程只是阻塞 . 如果我在该点(socket.recv)上放置一个断点,它可能会收到数据,但如果我正常运行它会无限期地阻塞 . 我不确定为什么调试它会影响它,也许会引入延迟?我可以在wireshark中看到客户端正在发送消息而服务器确认它,但它永远不会从recv()返回 .

任何帮助将不胜感激 . 我浪费了太多时间在最有可能是一个简单的bug上 .

2 回答

  • 2

    self._socket.recv 是阻止通话 . 它将阻塞,直到它在套接字上接收数据 . 我认为问题是:

    data = True
    while data:
                data = self._socket.recv(4096)  #BLOCKS HERE 99% OF THE TIME
                message+=data.decode()
    

    服务器接收数据但再次进入循环并等待进一步的数据 . 退出循环的标准是什么?如果客户端发送数据但未断开连接,则循环将始终处于活动状态 . 只有当客户端断开连接时,循环才会中断 .

  • 0

    我相信你为自己制造的东西过于复杂 . 请参阅Python Cookbook中的以下示例:

    from socket import AF_INET, SOCK_STREAM, socket
    from concurrent.futures import ThreadPoolExecutor
    
    def echo_client(sock, client_addr):
        '''
        Handle a client connection
        '''
        print('Got connection from', client_addr)
        while True:
            msg = sock.recv(65536)
            if not msg:
                break
            sock.sendall(msg)
        print('Client closed connection')
        sock.close()
    
    def echo_server(addr):
        print('Echo server running at', addr)
        pool = ThreadPoolExecutor(128)
        sock = socket(AF_INET, SOCK_STREAM)
        sock.bind(addr)
        sock.listen(5)
        while True:
            client_sock, client_addr = sock.accept()
            pool.submit(echo_client, client_sock, client_addr)
    
    echo_server(('',15000))
    

    至少这个:

    while True:
            msg = sock.recv(65536)
            if not msg:
                break
    

    应该照顾你的阻止问题 .

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