我是(lua newbie / 3days)尝试调用存储在lua表中的函数,如下面的代码所示
function sayhello()
return "hello";
end
function saygoodbye()
return "goodbye";
end
funct = {
["1"] = sayhello,
["2"] = saygoodbye,
["name"] = "funct"
};
function say(ft,index)
local name = ft.name;
print("\nName : " .. name .. "\n");
local fn = ft.index;
fn();
end
say(funct,"1"); -- attempt to call local 'fn' (a nil value)
say(funct,"2"); -- attempt to call local 'fn' (a nil value)
-- the Name funct prints in both cases
我收到错误尝试调用本地'fn'(一个零值)名称功能在两个说来电话中打印 .
谢谢
2 回答
你要
因为
相当于
这被描述为Programming in Lua书中常见的初学者错误 . 如果你犯了错误,你知道你已经开始学习了 . @lhf的答案是正确的,但我只是想为其他访问此问题的人强调这本精彩的书[Lua中的Praogramming](https://www.lua.org/pil/2.5.html) .