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如何在Javascript中对多个变量进行相同的替换

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我想对多个变量做同样的替换 . 在这里's an example that works, but I have to write the replace statement for each variable. I could make the replace a function and call the function for each variable, but I was wondering if there'是一种更有效的方式在一行中完成它，比如 string1,string2,string3(replace...

<script>
string1="I like dogs, dogs are fun";
string2="The red dog and the brown dog died";
string3="The dog likes to swim in the ocean";
string1=string1.replace(/dog/g,'cat');
string2=string2.replace(/dog/g,'cat');
string3=string3.replace(/dog/g,'cat');

alert(string1+"\n"+string2+"\n"+string3);
</script>
javascript string replace

1 回答

  • 1

    改为使用数组，并使用 .map 到一个新数组，在每个数组上执行 replace 操作：

    const dogToCat = str => str.replace(/dog/g,'cat');
const strings = [
  "I like dogs, dogs are fun",
  "The red dog and the brown dog died",
  "The dog likes to swim in the ocean"
];
console.log(
  strings
    .map(dogToCat)
    .join('\n')
);

    如果你必须使用独立变量并重新分配给它们，那么你可以对结果进行解构，虽然它是一个好主意（如果可能， const s更可取）：

    const dogToCat = str => str.replace(/dog/g, 'cat');
let string1 = "I like dogs, dogs are fun";
let string2 = "The red dog and the brown dog died";
let string3 = "The dog likes to swim in the ocean";

([string1, string2, string3] = [string1, string2, string3].map(dogToCat));
console.log(string1 + "\n" + string2 + "\n" + string3);
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