我正在使用dplyr和扫帚组合，并尝试根据数据组内部的条件拟合回归模型 . 最后，我想提取每组的回归系数 .

到目前为止，我得到了所有组的相同拟合结果（每组用字母 a:f 分隔） . 这是主要问题 .

library(dplyr)
library(minpack.lm)
library(broom)

direc <- rep(rep(c("North","South"),each=20),times=6)
V <- rep(c(seq(2,40,length.out=20),seq(-2,-40,length.out=20)),times=1)
DQ0 = c(replicate(2, sort(runif(20,0.001,1))))
DQ1 = c(replicate(2, sort(runif(20,0.001,1))))
DQ2 = c(replicate(2, sort(runif(20,0.001,1))))
DQ3 = c(replicate(2, sort(runif(20,0.001,1))))
No  =  c(replicate(1,rep(letters[1:6],each=40)))

df <-   data.frame(direc,V,DQ0,DQ1,DQ2,DQ3,No)

适合条件可描述如下; direc=North 并且如果 V<J1 与公式 exp((-t_pw)/f0*exp(-del1*(1-V/J1)^2)) 拟合，如果 direc=South 和 V>J2 符合相同的公式 . 在这两种情况下，如果 V<J1 ＆ V>J2 不满足，则为每种情况返回 1 .

UPDATE 我发现条件 nls 可能是conditional-formula-for-nls，并附有此链接中的建议 .

nls_fit=nlsLM(DQ0~ifelse(df$direc=="North"&V<J1, exp((-t_pw)/f0*exp(-del1*(1-V/J1)^2)),1)*ifelse(df$direc=="South"&V>J2, exp((-t_pw)/f0*exp(-del2*(1-V/J2)^2)),1)
            ,data=df,start=c(del1=1,J1=15,del2=1,J2=-15),trace=T)

nls_fit

Nonlinear regression model
  model: DQ0 ~ ifelse(df$direc == "North" & V < J1, exp((-t_pw)/f0 * exp(-del1 *     (1 - V/J1)^2)), 1) * ifelse(df$direc == "South" & V > J2,     exp((-t_pw)/f0 * exp(-del2 * (1 - V/J2)^2)), 1)
   data: df
   del1      J1    del2      J2 
  1.133  23.541   1.079 -20.528 
 residual sum-of-squares: 16.93

Number of iterations to convergence: 4 
Achieved convergence tolerance: 1.49e-08

另一方面，当我尝试适应其他列，如DQ1，DQ2和DQ3;

我试过nls_fit = nlsLM（df [，3：6] ~elelse（.....

Error in nls.lm(par = start, fn = FCT, jac = jac, control = control, lower = lower, : evaluation of fn function returns non-sensible value!

现在问题归结为多列拟合 . 如何安装多列 DQ0:DQ3 ？我检查了how to succinctly write a formula with many variables from a data frame?但找不到我的数据框中使用的解决方案 .

另外，当我在其组内部拟合 DQ0 列时，您可以从输出中看到，为所有组生成相同的Del和J参数 a:f

df_new<- df%>%
  group_by(No)%>%
  do(data.frame(model=tidy()))>%
  ungroup

df_new

Source: local data frame [24 x 6]

   No model.term model.estimate model.std.error model.statistic model.p.value
1   a       del1       1.132546        9024.255    1.255002e-04     0.9999000
2   a         J1      23.540764      984311.373    2.391597e-05     0.9999809
3   a       del2       1.079182       27177.895    3.970809e-05     0.9999684
4   a         J2     -20.527520     2362268.839   -8.689748e-06     0.9999931
5   b       del1       1.132546        9024.255    1.255002e-04     0.9999000
6   b         J1      23.540764      984311.373    2.391597e-05     0.9999809
7   b       del2       1.079182       27177.895    3.970809e-05     0.9999684
8   b         J2     -20.527520     2362268.839   -8.689748e-06     0.9999931
9   c       del1       1.132546        9024.255    1.255002e-04     0.9999000
10  c         J1      23.540764      984311.373    2.391597e-05     0.9999809
.. ..        ...            ...             ...             ...           ...
r if-statement dplyr nls