首页 文章

Python设置docstring并获取动态生成的classmethod的方法名称

提问于
浏览
1

我正在尝试获取/设置动态创建的类方法的名称和文档字符串,如下所示,但我很难确定如何做到这一点:

import sys
import inspect

class test(object):
    pass

@classmethod
def genericFunc(cls, **kwargs):
    print "function:", (inspect.stack()[0][3])
    print "kwargs:", kwargs

function_list = ['myF1', 'myF2']
for func in function_list:
    setattr(test, func, genericFunc)
    #set docstring for func here?

if __name__ == '__main__':
    x = test()
    print "docstring:", x.myF1.__doc__
    x.myF1(arg1="foo")
    y = test()
    print "docstring:", y.myF2.__doc__
    y.myF2(arg1="foo", arg2="bar")
    sys.exit()

目前的输出是:

docstring: None
function: genericFunc
kwargs: {'arg1': 'foo'}
docstring: None
function: genericFunc
kwargs: {'arg1': 'foo', 'arg2': 'bar'}

我想拥有的是:

docstring: description of myF1
function: myF1
kwargs: {'arg1': 'foo'}
docstring: description of myF2
function: myF2
kwargs: {'arg1': 'foo', 'arg2': 'bar'}

在for循环中我尝试了 setattr(test.func, "__doc__", "description of %s" % func) ,这导致了一个AttributeError异常(类型对象'test'没有属性'func'),如果我硬编码'test.myF1'而不是'test.func',我得到属性 '__doc__' 'instancemethod'不可写的AttributeError .

最后,inspect.stack()返回"genericFunc"而不是动态函数名('myF1'或'myF2'),是否可以获取/设置后者,以便我可以在genericFunc中检查方法的 __name__ 的值,以执行某些操作,具体取决于它的 Value ?

1 回答

  • 1

    您的泛型函数本身没有文档字符串 . 当我添加文档字符串时,这对我很好:

    import inspect
    
        class test(object):
            pass
    
        @classmethod
        def genericFunc(cls, **kwargs):
            """ I'm a docstring"""
            print "function:", (inspect.stack()[0][3])
            print "kwargs:", kwargs
    
        function_list = ['myF1', 'myF2']
        for func in function_list:
            setattr(test, func, genericFunc)
            #set docstring for func here?
    
        if __name__ == '__main__':
            x = test()
            print "docstring:", x.myF1.__doc__
            x.myF1(arg1="foo")
            y = test()
            print "docstring:", y.myF2.__doc__
            y.myF2(arg1="foo", arg2="bar")
    

    另外,为什么sys.exit()结束了?结果,我得到:

    docstring:  I'm a docstring
    function: genericFunc
    kwargs: {'arg1': 'foo'}
    docstring:  I'm a docstring
    function: genericFunc
    kwargs: {'arg1': 'foo', 'arg2': 'bar'}
    

相关问题