我有一个以模式发送的python代码，其中灯必须闪烁 . （比如说101010.每次运行代码时模式都可能不同） . 当它无限地执行时，我想要一个中断（再次由python代码发送）来保存灯的当前条件（比如运行1的序列）并执行特定任务，如关灯10秒钟然后恢复序列 . 一种方法是通过使中断引脚为高电平来中断程序 . 问题是这可以由pyserial控制高/低 . 所以一个简单的伪代码将是：

PYTHON部分代码：

Read the sequence:
Send the sequence to the arduino board using pyserial.
while(1)
{
    Run a timer for 15 second.
    When the timer overflows interrupt the arduino.
}

ARDUINO代码的一部分：

Read the sequence 
while (1)
{
    keep repeating the sequence on the LED.
}

// if interrupted on pin2  // assuming pin2 has the interrupt procedure
// Pyserial has to enable the interrupt WITHOUT using a switch for enabling the pin.

ISR 
{
    Save the present state of execution.
    Turn off the LED.
 }

更好的理解：

我 Build 了小代码来表明我的疑虑：

ARDUINO的代码是：

int ledpin1 = 13;

int speedy;

int patterns;

void setup()

{

  Serial.begin(9600);

  Serial.print("Program Initiated: \n");

  pinMode(ledpin1,OUTPUT);

  //activate the blackout ISR when a interrupt is achieved at a certain pin. In this case pin2 of the arduino

  attachInterrupt(0,blackout,CHANGE);

}

void loop()

{

  if (Serial.available()>1)

  {

    Serial.print("starting loop \n");

    patterns = Serial.read();

    patterns = patterns-48;

    speedy = Serial.read();

    speedy = (speedy-48)*1000;

    while(1)

    {

      patterns = !(patterns);

      Serial.print(patterns);

      digitalWrite(ledpin1,patterns);

      delay(speedy);

    }

  }

}

/*

void blackout()

{

  // ***Save the present state of the LED(on pin13)***

  Serial.print ("The turning off LED's for performing the python code\n");

  digitalWrite(ledpin,LOW);

  //wait for the Python code to complete the task it wants to perform, 

  //so got to dealy the completion of the ISR

  delay(2000);// delay the whole thing by 2 seconds

  //***Continue with the while loop by setting the condition of the light to the saved condition.***

}

*/

================================================== ================================

PYTHON FRONT的代码是：

import serial

import time

patterns=1

speedy=1

ser = serial.Serial()

ser.setPort("COM4")

ser.baudrate = 9600

ser.open()

def main():

    if (ser.isOpen()):

        #while(1):

        ser.write(patterns)

        ser.write(speedy)

        blackoutfunc()

        #ser.close()



def blackoutfunc():

    while(1):

        time.sleep(2)

        print "Performing operations as required"

================================================== =============================

现在我的问题是：

1）有没有办法能够激活“中断ISR”，具体取决于引脚的条件（在这种情况下，引脚2是INT0引脚），而不使用引脚上的物理开关 . 因此，引脚状态必须由软件操纵 .

2）是否可以执行停电功能注释中提到的操作？

3）在python代码中，可以只发送一次数据（即模式，快速），并使arduino以无限的方式执行模式，而不再通过 serial.write 命令发送数据 . 因此避免在 ser.isOpen() 之后的 while(1) 循环 .