我有多个switch语句,但在某些情况下我需要常见的情况 . 所以,我正在尝试
OR operator => ||
例:
<ng-container [ngSwitch]="options">
<ng-container *ngSwitchCase="'a'">Code A</ng-container>
<ng-container *ngSwitchCase="'b'">Code B</ng-container>
<ng-container *ngSwitchCase="'c'">Code C</ng-container>
<ng-container *ngSwitchCase="'d' || 'e' || 'f'">Common Code</ng-container>
<ng-container *ngSwitchDefault>Code Default</ng-container>
</ng-container>
Output:
if case = 'd' returns Common Code
else if case = 'e' and 'f' returns the Code Default
这里的第二个案例包含多个案例,现在默认情况下 case 'd'
仅在 case 'e' and 'f'
工作且不起作用 .
我在 ngSwitchCase
docs中看不到任何多个案例:
https://angular.io/docs/ts/latest/api/common/index/NgSwitchCase-directive.html https://angular.io/docs/ts/latest/api/common/index/NgSwitch-directive . HTML
Doesn't Angular 2 supports the || operator in the ngSwitchCase?
1 回答
如果你评估
'd' || 'e' || 'f'
,结果是'd'
,当options
不是'd'
时,那么它不会't match. You can'这样使用ngSwitchCase
.这可行: