对于我的df中的每一列,我想从上一行(行[n 1] -row [n])中减去当前行,但是我遇到了困难 .
我的代码如下:
#!/usr/bin/python3
from pandas_datareader import data
import pandas as pd
import fix_yahoo_finance as yf
yf.pdr_override()
import os
stock_list = ["BHP.AX", "CBA.AX", "RHC.AX", "TLS.AX", "WOW.AX", "^AORD"]
# Function to get the closing price of the individual stocks
# from the stock_list list
def get_closing_price(stock_name, specific_close):
symbol = stock_name
start_date = '2010-01-01'
end_date = '2016-06-01'
df = data.get_data_yahoo(symbol, start_date, end_date)
sym = symbol + " "
print(sym * 10)
df = df.drop(['Open', 'High', 'Low', 'Adj Close', 'Volume'], axis=1)
df = df.rename(columns={'Close': specific_close})
# https://stackoverflow.com/questions/16729483/converting-strings-to-floats-in-a-dataframe
# df[specific_close] = df[specific_close].astype('float64')
print(type(df[specific_close]))
return df
# Creates a big DataFrame with all the stock's Closing
# Price returns the DataFrame
def get_all_close_prices(directory):
count = 0
for stock_name in stock_list:
specific_close = stock_name.replace(".AX", "") + "_Close"
if not count:
prev_df = get_closing_price(stock_name, specific_close)
else:
new_df = get_closing_price(stock_name, specific_close)
# https://stackoverflow.com/questions/11637384/pandas-join-merge-concat-two-dataframes
prev_df = prev_df.join(new_df)
count += 1
prev_df.to_csv(directory)
return prev_df
# THIS IS THE FUNCTION I NEED HELP WITH
# AS DESCRIBED IN THE QUESTION
def calculate_return(df):
count = 0
# for index, row in df.iterrows():
print(df.columns[0])
for stock in stock_list:
specific_close = stock.replace(".AX", "") + "_Close"
print(specific_close)
# https://stackoverflow.com/questions/15891038/change-data-type-of-columns-in-pandas
pd.to_numeric(specific_close, errors='ignore')
df.columns[count].diff()
count += 1
return df
def main():
# FINDS THE CURRENT DIRECTORY AND CREATES THE CSV TO DUMP THE DF
csv_in_current_directory = os.getcwd() + "/stk_output.csv"
# FUNCTION THAT GETS ALL THE CLOSING PRICES OF THE STOCKS
# AND RETURNS IT AS ONE COMPLETE DATAFRAME
df = get_all_close_prices(csv_in_current_directory)
# THIS PRINTS OUT WHAT IS IN "OUTPUT 1"
print(df)
# THIS FUNCTION IS WHERE I HAVE THE PROBLEM
df = calculate_return(df)
# THIS SHOULD PRINT OUT WHAT IS IN "EXPECTED OUTPUT"
print(df)
# Main line of code
if __name__ == "__main__":
main()
Question:
对于每一列,我想从前一行(行[n 1] -row [n])中减去当前行,并将此值分配给数据帧末尾的新列,作为 stock_name + "_Earning"
的新列 . 我的预期输出(参见:预期输出)是我仍然有原始的 df
,如 Output 1 所示,但有6个额外的列,第一行是空的,以及行的差异(行[n 1] -row [n ])在各栏中 .
Problem Faced:
使用当前代码 - 我收到以下错误,我试图摆脱
AttributeError:'str'对象没有属性'diff'
Things I Have Tried:
我试过的一些事情:
Expected Output:
BHP_Close CBA_Close RHC_Close TLS_Close WOW_Close ^AORD BHP_Earning CBA_Earning RHC_Earning TLS_Earning WOW_Earning ^AORD_Earning
Date
2010-01-03 40.255699 54.574299 11.240000 3.45 27.847300 4889.799805
2010-01-04 40.442600 55.399799 11.030000 3.44 27.679100 4939.500000 0.186901 0.8255 -0.21 -0.01 -0.1682 49.70020000
Output 1:
BHP_Close CBA_Close RHC_Close TLS_Close WOW_Close ^AORD_Close
Date
2010-01-03 40.255699 54.574299 11.240000 3.45 27.847300 4889.799805
2010-01-04 40.442600 55.399799 11.030000 3.44 27.679100 4939.500000
2010-01-05 40.947201 55.678299 11.180000 3.38 27.629601 4946.799805
... ... ... ... ... ... ...
2016-05-30 19.240000 78.180000 72.730003 5.67 22.389999 5473.600098
2016-05-31 19.080000 77.430000 72.750000 5.59 22.120001 5447.799805
2016-06-01 18.490000 76.500000 72.150002 5.52 21.799999 5395.200195
1 回答
这是一种简单快捷的方式来做你想做的事情:
结果:
我们可以使用shift成员函数向上(或向下)移动整个数据框 . 然后我们只需要从原始中减去它,并重命名列 .
结果:
然后将结果与原始结果一起加入 .
结果:
编辑:重新访问您的帖子后,看起来您试图在包含字符串的某些列上执行此操作?将它们过滤掉或转换为支持“ - ”运算符的数据类型 .