如何确定何时给出一组具有最小角度的三角形三角形[关闭]

1 回答

• 1

  如果这是您的完整源代码，则缺少某些部分 . 您可以通过写入导入 <stdio.h>

  #include <stdio.h>
  

  在代码的开头 .

  此外，没有 main() { ... } . 您也可以处理两个角度相等的情况 sinTheta == sinTheta1 .

  #include <stdio.h>
  
  int main() {
  
  float a, b, c, a1, b1, c1;
  float sinTheta, sinTheta1;
  
  printf ("Please enter values for a, b, c\n");
  scanf ("%f%f%f", &a, &b, &c);
  
  printf ("Please enter values for a1, b1, c1\n");
  scanf ("%f%f%f", &a1, &b1, &c1);
  
  
  sinTheta=a/c;
  sinTheta1=a1/c1;
  
  if (sinTheta < sinTheta1) {
      printf ("the triangle a b c has the smaller angle\n");
  }
  else if (sinTheta > sinTheta1) {
       printf ("The triangle a1, b1, c1 has the smaller angle\n");
  }
  else 
  {
      printf ("the angles are the same\n");
  }
  return 0;
  }
  

  BTW： b 的值是多余的 .

  编辑：

  快速而肮脏的方法：

  #include <stdio.h>
  
  int main() {
  
  float a, c;
  float sinTheta;
  
  float sinThetaMin;
  int nMin;
  int nTriangle=2;  // specifies the number of triangles
  int i;
  
  
  for (i=0; i<nTriangle; i++) {
      printf ("Please enter values for a, c for triangle %d\n", i+1);
      scanf ("%f%f", &a, &c);
      sinTheta = a/c;
      printf("%f\n", sinTheta);
      if (i == 0) {
          sinThetaMin = sinTheta;
          nMin = i+1;
      }
      else {
          if (sinTheta < sinThetaMin) {
                  sinThetaMin = sinTheta;
                  nMin = i+1;
          }
      }
  
  }
  
  printf("Smallest triangle is number %d with a/c = %f\n", nMin, sinThetaMin);
  
  return 0;
  }
  

  回复于 2024-05-18T15:36:18+08:00