我正在构建一个python脚本来解决Riemann的Paradox . 我们的想法是输入一个输入的数字,然后在1 / 2,1 / 3,1 / 4,1 / 5 ...中加/减1,直到输入数字为止 . 由于每次进行比较时都会回调我的比较并添加/减去类,因此我遇到了递归错误 .
我的代码如下:
import math
#declare values of variables before they are referenced
goal = float(input("What number are you trying to achieve?"))
current_number = float(1)
negatives = (2)
positives = (3)
#-----------------------------------------------------
def add(goal,current_number,positives,negatives): #define the add operation for when the current number is less than the goal
current_number = current_number+(1/positives) #add current fraction to the current number
positives = positives+2 #Set the next additional fraction
comparison(goal,current_number,positives,negatives) #go to comparision of the current number to the goal
def subtract(goal,current_number,positives,negatives): #define the subtract operation for when the current number is greater than the goal
current_number = current_number-(1/negatives) #subtract current fraction from the current number
negatives = negatives+2 #set the next subtractional fraction
comparison(goal,current_number,positives,negatives) #go to comparision of the current number to the goal
def comparison(goal,current_number,positives,negatives): #define comparison between the current number to the goal
if current_number < goal:
add(goal,current_number,positives,negatives) #if the current number is less than the goal, go to add the next fraction to it
if current_number > goal:
subtract(goal,current_number,positives,negatives) #if the current number is greater than the goal, do to subtract the next fraction from it
if current_number == goal:
print("The equation for your number is 1+1/3...")
print("+1/",positives)
print("...-1/2...")
print("-1/",negatives)
#if the current number is equal to the goal, print the results
comparison(goal,current_number,positives,negatives) #do the comparison between the current number and the goal
我想知道我能做些什么来解决这个问题 .
2 回答
您不需要添加和减去函数,因为添加负数与减去相同 .
此外,我已修复您的代码,调用一个函数调用您调用它的函数是导致您的递归错误的函数 .
在
current_number == goal
中您正在比较浮点数并使用==
通常不是the right way to do it .你可能想increase the maximum recursion depth .
将
print(current_number)
添加为comparison()
函数的第一行,并查看current_number
如何收敛/偏离目标 .