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如何在Python中将epoch（unix时间）之后的datetime对象转换为毫秒？

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我有一个Python datetime 对象，我想转换为unix时间，或者自1970年代以来的秒/毫秒 .

我该怎么做呢？

python datetime epoch

13 回答

  • 0

    在我看来，最简单的方法是

    import datetime

epoch = datetime.datetime.utcfromtimestamp(0)

def unix_time_millis(dt):
    return (dt - epoch).total_seconds() * 1000.0
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  • 92

    在Python 3.3中，添加新方法 .

    datetime.timestamp()

    https://docs.python.org/3.3/library/datetime.html#datetime.datetime.timestamp

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  • 11
    >>> import datetime
>>> # replace datetime.datetime.now() with your datetime object
>>> int(datetime.datetime.now().strftime("%s")) * 1000 
1312908481000

    或者时间模块的帮助（没有日期格式化）：

    >>> import datetime, time
>>> # replace datetime.datetime.now() with your datetime object
>>> time.mktime(datetime.datetime.now().timetuple()) * 1000
1312908681000.0

    在以下帮助下回答：http://pleac.sourceforge.net/pleac_python/datesandtimes.html

    文档：

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  • 1

    您可以使用Delorean在空间和时间旅行！

    import datetime
import delorean
dt = datetime.datetime.utcnow()
delorean.Delorean(dt, timezone="UTC").epoch

    http://delorean.readthedocs.org/en/latest/quickstart.html

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  • 0
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  • 15

    我是这样做的：

    from datetime import datetime
from time import mktime

dt = datetime.now()
sec_since_epoch = mktime(dt.timetuple()) + dt.microsecond/1000000.0

millis_since_epoch = sec_since_epoch * 1000
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  • 380
    from datetime import datetime
from calendar import timegm

# Note: if you pass in a naive dttm object it's assumed to already be in UTC
def unix_time(dttm=None):
    if dttm is None:
       dttm = datetime.utcnow()

    return timegm(dttm.utctimetuple())

print "Unix time now: %d" % unix_time()
print "Unix timestamp from an existing dttm: %d" % unix_time(datetime(2014, 12, 30, 12, 0))
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  • -9
    >>> import datetime
>>> import time
>>> import calendar

>>> #your datetime object
>>> now = datetime.datetime.now()
>>> now
datetime.datetime(2013, 3, 19, 13, 0, 9, 351812)

>>> #use datetime module's timetuple method to get a `time.struct_time` object.[1]
>>> tt = datetime.datetime.timetuple(now)
>>> tt
time.struct_time(tm_year=2013, tm_mon=3, tm_mday=19, tm_hour=13, tm_min=0, tm_sec=9,     tm_wday=1, tm_yday=78, tm_isdst=-1)

>>> #If your datetime object is in utc you do this way. [2](see the first table on docs)
>>> sec_epoch_utc = calendar.timegm(tt) * 1000
>>> sec_epoch_utc
1363698009

>>> #If your datetime object is in local timeformat you do this way
>>> sec_epoch_loc = time.mktime(tt) * 1000
>>> sec_epoch_loc
1363678209.0

    [1] http://docs.python.org/2/library/datetime.html#datetime.date.timetuple

    [2] http://docs.python.org/2/library/time.html

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  • 1

    这是另一种形式的解决方案，用于规范您的时间对象：

    def to_unix_time(timestamp):
    epoch = datetime.datetime.utcfromtimestamp(0) # start of epoch time
    my_time = datetime.datetime.strptime(timestamp, "%Y/%m/%d %H:%M:%S.%f") # plugin your time object
    delta = my_time - epoch
    return delta.total_seconds() * 1000.0
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  • 14

    一点熊猫代码：

    import pandas

def to_millis(dt):
    return int(pandas.to_datetime(dt).value / 1000000)
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  • 3
    import time
seconds_since_epoch = time.mktime(your_datetime.timetuple()) * 1000
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  • 86

    这是我根据上面的答案做的功能

    def getDateToEpoch(myDateTime):
    res = (datetime.datetime(myDateTime.year,myDateTime.month,myDateTime.day,myDateTime.hour,myDateTime.minute,myDateTime.second) - datetime.datetime(1970,1,1)).total_seconds()
    return res

    你可以像这样包装返回的值：str（int（res））返回没有十进制值的它用作字符串或只用int（没有str）

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  • 7

    另一个解决方案是将隐藏日期时间改为unixtimestampmillis .

    private static readonly DateTime UnixEpoch = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc);

    public static long GetCurrentUnixTimestampMillis()
    {
        DateTime localDateTime, univDateTime;
        localDateTime = DateTime.Now;          
        univDateTime = localDateTime.ToUniversalTime();
        return (long)(univDateTime - UnixEpoch).TotalMilliseconds;
    }
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