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处理来自Arduino的串行读取导致Java PApplet错误

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我正在阅读一个arduino草图的序列数据，我上传到一个青少年2.0 /这也发生在运行常规arduino时 . 然后我将分裂字符串并转换为具有Processing的int（）函数的整数数组，以便能够触发声音 . arduino草图正在读取电容式传感器数据 . 它运行良好大约10-15s然后开始抛出以下错误 .

Exception in thread "Animation Thread" java.lang.NullPointerException
        at processing.core.PApplet.parseInt(PApplet.java:9127)
        at processing.core.PApplet.parseInt(PApplet.java:9113)
        at NightGames_Tree.draw(NightGames_Tree.java:59)
        at processing.core.PApplet.handleDraw(PApplet.java:2266)
        at processing.core.PGraphicsJava2D.requestDraw(PGraphicsJava2D.java:243)
        at processing.core.PApplet.run(PApplet.java:2140)
        at java.lang.Thread.run(Thread.java:695)

我的代码如下：在Arduino中：

#include <CapacitiveSensor.h>

CapacitiveSensor   cs_4_2 = CapacitiveSensor(4,2);        

void setup()                    
{
   cs_4_2.set_CS_AutocaL_Millis(0xFFFFFFFF);     // turn off autocalibrate on channel 1 - just as an example
   Serial.begin(9600);
}

void loop()                    
{
    long start = millis();
    long total1 =  cs_4_2.capacitiveSensor(30);

    Serial.print(millis() - start);        // check on performance in milliseconds
    Serial.print("\t");                    

    Serial.print(total1);                  // print sensor output 1
    Serial.println("\t");

    delay(100);                            
}

进行中：

import ddf.minim.spi.*;
    import ddf.minim.signals.*;
    import ddf.minim.*;
    import ddf.minim.analysis.*;
    import ddf.minim.ugens.*;
    import ddf.minim.effects.*;

    import processing.serial.*;

    Minim minim;
    AudioPlayer tree1;
    AudioPlayer tree2;

    Serial myPort;
    String val;

void setup(){

    String portName = Serial.list()[12]; // calls on the port which teensy is on
    myPort = new Serial(this, portName, 9600);
    println(Serial.list()); // prints list of ports that processing can access

    //setup sound

    minim = new Minim(this);
    tree1 = minim.loadFile("tree1.aif");

}

void draw()
{


    if (myPort.available() > 0) {
        val = myPort.readStringUntil('\n');
        int[] list = int(split(val, '\t')); // splits string into list based on tab after
    int sum = 0;
    int sum1 = 0;
 //  print(list.length);

      sum = sum + list[0];
      sum1 = sum1 + list[1];

    print(sum);
    print('\t');
    print(sum1);
    print('\t');
    print('\n');

   //print(val);

    if (sum1 > 500) {
      tree1.play(0);
    } else if (sum1 <500){
    }

  }
}

运行一段时间后出现错误时，Processing会突出显示这行代码

int[] list = int(split(val, '\t'));

在此先感谢您的帮助 . 我在Mac上运行它 .

java arduino processing

2 回答

  • 0

    我在一个Windows机器上运行它，使用Processing 3.0a4和Arduino 1.6.3在Arduino上，我评论了所有与电容式传感器库有关的因为我没有它 . `

    //#include <CapacitiveSensor.h>
//CapacitiveSensor   cs_4_2 = CapacitiveSensor(4,2);        
void setup()                    
{
// cs_4_2.set_CS_AutocaL_Millis(0xFFFFFFFF);     
// turn off autocalibrate on channel 1 - just as an example

    Serial.begin（9600）; }

    void loop()                    
{
long start = millis();
// long total1 =  cs_4_2.capacitiveSensor(30);

Serial.print(millis() - start);        
// check on performance in milliseconds
Serial.print("\t");                    

//Serial.print(total1);                  // print sensor output 1
Serial.println("\t");

delay(100);                            
}

    在处理中，我用声音文件注释掉了这一行 . 我得到的错误指向这一行：

    int [] list = int（split（val，'\ t'））;

    似乎有一种类型不匹配允许列表流一小段但它们会阻塞处理器 .

    回复于
  • 0

    原来处理是检测到空对象，因此添加对空对象的检查解决了问题 . 精简代码是：

    import processing.serial.*;

Serial myPort;
String val;

void setup(){
  String portName = Serial.list()[12]; // calls on the port which teensy is on
  myPort = new Serial(this, portName, 9600);
} 

void draw()
{
  if (myPort.available() > 0) {
    val = myPort.readStringUntil('\n');
    if (val!=null){
    int[] list = int(split(val, '\t')); // splits string into list based on tab 

    int sum = 0;
    int sum1 = 0;
    int sum2 = 0;

    sum = sum + list[0];
    sum1 = sum1 + list[1];
    sum2 = sum2 + list[2];

    print(sum);
    print('\t');
    print(sum1);
    print('\t');
    print(sum2);
    print('\t');
    print('\n');
    }
  }
}
    回复于

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