级别因子分解无法转换为ggplot barplot变量顺序-Java 学习之路

我试图在ggplot堆积条形图中对变量进行排序 . 到目前为止，这是我的代码：

levels(rs$Site) <- c("Mature","Little East","Upper Fill","Lower Fill")
# I have rearranged the levels to the desired order, but the output looks like 
# c("Little East","Lower Fill","Upper Fill","Mature")

library(ggplot2)
library(scales)
ggplot(rs, aes(x = Site)) + geom_bar(aes(fill = At.Mature), position = 'fill') +
    scale_x_discrete(limits=unique(rs$Site)) +
    coord_flip()

但是，数据从上到下绘制为：

c("Mature","Upper Fill","Lower Fill","Little East")
# Notice this is simply a reverse of the output of the level reorder above

我尝试使用factor（）重新排序级别，但结果保持不变 .

为什么“小东方”走向终点（图的底部）？我怎样才能解决这个问题？

1 回答

我们可以使用订单中指定的 levels 再次调用 factor

rs$Site <- factor(rs$Site, levels = c("Mature", "Little East", 
          "Upper Fill", "Lower Fill"))

并在 scale_x_discrete 中，使用 levels(rs$Site)

ggplot(rs, aes(x = Site)) +  
      geom_bar(aes(fill = At.Mature), position = 'fill') + 
      scale_x_discrete(limits = levels(rs$Site)) + 
      coord_flip()

数据

set.seed(24)
rs <- data.frame(Site = sample(c("Mature","Little East",
"Upper Fill","Lower Fill"), 30, replace = TRUE), 
   At.Mature = sample(c("Yes", "No"), 30, replace = TRUE))

分配 levels 是有风险的，因为它可以更改值，例如

set.seed(24)
v1 <- factor(sample(LETTERS[1:5], 20, replace = TRUE))
v1
#[1] B B D C D E B D E B D B D D B E A A C A
#Levels: A B C D E
levels(v1) <- c('C', 'D', 'E', 'A', 'B')
v1
#[1] D D A E A B D A B D A D A A D B C C E C  ### values got replaced
#Levels: C D E A B

回复于 2024-05-03T03:30:55+08:00

级别因子分解无法转换为ggplot barplot变量顺序

1 回答

数据

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