我有以下数据管道但是有一些混淆解释输出 . 任何帮助深表感谢 .

# tune the hyperparameters via a cross-validated grid search

from sklearn.ensemble import RandomForestClassifier
print("[INFO] tuning hyperparameters via grid search")
params = {"max_depth": [3, None],
          "max_features": [1, 2, 3, 4],
          "min_samples_split": [2, 3, 10],
          "min_samples_leaf": [1, 3, 10],
          "bootstrap": [True, False],
          "criterion": ["gini", "entropy"]}

model = RandomForestClassifier(50)
grid = RandomizedSearchCV(model, params, cv=10, scoring = 'roc_auc')
start = time()
grid.fit(X_train, y_train)

# evaluate the best grid searched model on the testing data

print("[INFO] grid search took {:.2f} seconds".format(
    time() - start))
acc = grid.score(X_train, y_train)
print("[INFO] grid search accuracy: {:.2f}%".format(acc * 100))
print("[INFO] grid search best parameters: {}".format(
grid.best_params_))

查看交叉验证的培训分数：

rf_score_train = grid.score(X_train, y_train)
rf_score_train

0.87845540607872441

现在使用这个训练模型来预测测试集：

rf_score_test = grid.score(X_test, y_test)
rf_score_test

0.72482993197278911

但是，当我将此模型的预测视为一个数组并使用外部roc_auc_score指标将此预测与实际结果进行比较时，我得到的测试集上面的GridSearchCV'roc_auc'得分完全不同 .

model_prediction = grid.predict(X_test)
model_prediction

array([0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 
0, 0,0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 
0,0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 1, 0, 1, 1, 0, 1, 0, 
0,0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 
0,0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 
0,0, 0, 0, 1, 0, 0, 0, 0, 1, 1, 1, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 
0,0, 1, 0, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 
0,0, 1, 0, 0, 0, 0, 0, 0])

实际结果：

actual_outcome = np.array(y_test)
actual_outcome

array([0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 1, 
0, 0,0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 
1,1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 
0,0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 1, 1, 0, 
0,0, 1, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 
1,0, 0, 0, 1, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 
0,0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1, 
0,0, 0, 1, 0, 0, 0, 1, 0])

在GridSearch之外使用roc_auc_score：

from sklearn.metrics import roc_auc_score
roc_accuracy = roc_auc_score(actual_outcome, model_prediction)*100
roc_accuracy

59.243197278911566

因此，在GridSearch中使用交叉验证的'roc_auc'得分我得到72左右，但当我在外部使用相同的预测'roc_auc_score'时我得到59.哪一个是正确的？我很迷惑 . 我在这里做错了吗？任何帮助深表感谢！

python scikit-learn roc sklearn-pandas grid-search