我的学校项目有问题 . 我在学校服务器上使用UNIX中的VIM编写它 . 当我在我的项目中插入记录时,会跳过姓氏 . 同时提示名字和姓氏,而不等待姓氏接收它的输入 . 见下文:
我的菜单是这样做的:
MENU(I)插入新记录(L)ast名称搜索(S)ave数据库到文件(R)ead数据库从文件(Q)uit输入选择:i插入新记录选择请输入员工姓氏:请输入员工的名字:
它正在跳过姓氏!
我需要在某处添加cout.flush()吗?当我在姓氏部分下面添加cout.flush()时,我收到此错误:
unixapps1:Lab1> make
g++ -o LSL lab1.cpp Employee.cpp
lab1.cpp: In function âEmployee createRecord()â:
lab1.cpp:41: error: âstruct std::istreamâ has no member named âflushâ
我的菜单代码是这样的:
int main() {
cout << "\n"
<< "************************************************************\n"
<< "Remember: Search for TODO's in VI before submitting project!\n"
<< "************************************************************\n\n";
char menu_choice;
string fileName;
// Create a database
LinkedSortedList<Employee> database;
while (true) {
// Display menu
cout << "MENU\n"
<< "(I)nsert new record\n"
<< "(L)ast name search\n"
<< "(S)ave database to a file\n"
<< "(R)ead database from a file\n"
<< "(Q)uit\n\n";
cout << "Enter choice: ";
cin >> menu_choice;
cout << endl;
switch (toupper(menu_choice)) {
case 'I':
cout << "Insert new record selected\n\n";
{database.insert(createRecord());}
break;
case 'L':
cout << "Last name search selected\n\n";
// TODO call function to search by last name
// TODO call search for Last Name
// TODO Print all matches found
{string searchVal = "";
database.find(searchVal);}
break;
case 'S':
cout << "Save database to a file selected\n\n";
// TODO call function to save database to file
// File I/O Save to file
cout << "Please enter a file name: " << endl;
cin >> fileName;
{char* file = (char*) fileName.c_str();
writeFile(file, database);}
break;
case 'R':
cout << "Read database from a file selected\n\n";
// TODOOA call function to read database from file
// File I/O Read file
cout << "Please enter a file name: " << endl;
cin >> fileName;
{char* file = (char*) fileName.c_str();
readFile(file, database);}
break;
case 'Q':
exit(EXIT_SUCCESS);
// default case:
default:
cout << "Invalid choice!\n\n"
<< "##### Please try again #####\n\n";
break;
cin >> menu_choice;
}
}
return 0;
}
这是我的 createRecord()
函数:
// Create the record to be inserted into the employee database
Employee createRecord() {
// Temporary variables for getting input from user
string stringInput = "";
int intInput = 0;
Employee newEmployee;
cout << "Please enter employee's Last Name: " << endl;
getline(cin, stringInput);
newEmployee.setLastName(stringInput);
cout << "Please enter employee's First Name: " << endl;
getline(cin, stringInput);
newEmployee.setFirstName(stringInput);
cout << "Please enter employee's ID: ";
getline(cin, stringInput);
stringstream myStream(stringInput);
myStream >> intInput;
newEmployee.setId(intInput);
cout << "Please enter employee's Salary: ";
getline(cin, stringInput);
myStream >> intInput;
newEmployee.setSalary(intInput);
cout << "Please enter employee's Department: ";
getline(cin, stringInput);
newEmployee.setDepartment(stringInput);
cout << "Please enter employee's Phone Number: ";
getline(cin, stringInput);
newEmployee.setPhoneNumber(stringInput);
cout << "Please enter employee's Address: ";
getline(cin, stringInput);
newEmployee.setAddress(stringInput);
cout << "Please enter employee's Hire Date: ";
getline(cin, stringInput);
newEmployee.setHireDate(stringInput);
}
2 回答
看起来输入流中仍然有换行符或其中的一部分 .
尝试使用
std::istream::ignore()
来吃输入流中的剩余字符 .您是否尝试过使用
cin.get()
而不是cout.flush()
?