Arduino和Raspberry Pi串口通信多个变量

1 回答

• 2

  考虑以下方法同时发送2个变量：

  int xpos, ypos;
  
      char x_tx_buffer[20], y_tx_buffer[20];
      char x_dummy_buffer[20];
      char y_dummy_buffer[20];
      char *p_x_tx_buffer, *p_y_tx_buffer;
  
      sprintf(x_dummy_buffer,"%d", xposs);
      sprintf(y_dummy_buffer,"%d", yposs);
  
      p_x_tx_buffer = &x_tx_buffer[0];
      *p_x_tx_buffer++ = x_dummy_buffer[0];
      *p_x_tx_buffer++ = x_dummy_buffer[1];
      *p_x_tx_buffer++ = x_dummy_buffer[2];
      *p_x_tx_buffer++ = x_dummy_buffer[3];
  
      p_y_tx_buffer = &y_tx_buffer[0];
      *p_y_tx_buffer++ = y_dummy_buffer[0];
      *p_y_tx_buffer++ = y_dummy_buffer[1];
      *p_y_tx_buffer++ = y_dummy_buffer[2];
      *p_y_tx_buffer++ = y_dummy_buffer[3];
      uart0_filestream = open("/dev/ttyAMA0", O_RDWR | O_NOCTTY | O_NDELAY);      //Open in non blocking read/write mode
      if (uart0_filestream == -1)
      {
          //ERROR - CAN'T OPEN SERIAL PORT
          printf("Error - Unable to open UART.  Ensure it is not in use by another application\n");
      }
      if (uart0_filestream != -1)
      {
          int countx = write(uart0_filestream, &x_tx_buffer[0], (p_x_tx_buffer - &x_tx_buffer[0]));       //Filestream, bytes to write, number of bytes to write
          int county = write(uart0_filestream, &y_tx_buffer[0], (p_y_tx_buffer - &y_tx_buffer[0]));       //Filestream, bytes to write, number of bytes to write
          if (countx < 0 || county < 0)
          {
              printf("UART TX error\n");
          }
      }
      close(uart0_filestream);
  

  您一次最多可以发送8个字节 . 记住这一点，你可以修改about代码，在同一个uart0_filestream中发送你的x和y值 .

  祝好运 .

  回复于 2024-04-28T11:34:51+08:00