Django REST：为OneToOne Field创建CRUD操作-Java 学习之路

我正在尝试为OneToOne字段创建基本的CRUD操作 . 登录时，用户无需设置配置文件 . 如何在需要时创建/更新/删除配置文件（假设用户已在数据库中）？

我的模型是Django REST的默认用户模型，并且：

class UserProfile(models.Model):
        user = models.OneToOneField(User)
        location = models.CharField(max_length=50,blank=True)
        title = models.CharField(max_length=80,blank=True)
        #picture = models.ImageField(upload_to='user_imgs', blank=True)
        website = models.URLField(blank=True)

我的视图集是：

class UserViewSet(viewsets.ModelViewSet):
    queryset = User.objects.all()
    serializer_class = UserSerializer
    filter_fields = ['id', 'username', 'email', 'first_name', 'last_name']

class UserProfileViewSet(viewsets.ModelViewSet):
    queryset = UserProfile.objects.all()
    serializer_class = UserProfileSerializer
    filter_fields = ['user_id', 'location', 'title', 'website']

并序列化：

class UserSerializer(serializers.HyperlinkedModelSerializer):
    class Meta:
        model = User
        email = serializers.EmailField()
        fields = ('id','username', 'email', 'first_name', 'last_name')


class UserProfileSerializer(serializers.HyperlinkedModelSerializer):
    user_id = serializers.CharField(source='user.id')

    class Meta:
        model = UserProfile
        fields = ('user_id', 'location','title','website')

2 回答

我相信你想要将配置文件创建限制为当前登录用户 . 您可以将配置文件的查询集过滤到当前用户，这样只有登录用户才能访问该用户的配置文件 .

class UserViewSet(viewsets.ModelViewSet):
    queryset = User.objects.all()
    serializer_class = UserSerializer
    filter_fields = ['id', 'username', 'email', 'first_name', 'last_name']


class UserProfileViewSet(viewsets.ModelViewSet):
    queryset = UserProfile.objects.all()
    serializer_class = UserProfileSerializer
    filter_fields = ['user_id', 'location', 'title', 'website']

    def get_queryset(self):
        return super(UserProfileViewSet, self).get_queryset().filter(
            user=self.request.user)

    def perform_create(self, serializer):
        serializer.save(user=user)

您将 user 字段设置为只读并保存在上述方法 perform_create 中，并始终分配给当前用户 .

class UserProfileSerializer(serializers.HyperlinkedModelSerializer):
    class Meta:
        model = UserProfile
        fields = ('user', 'location','title','website')
        read_only_fields = ('user',)

回复于 2024-05-04T12:34:01+08:00

它应该集中定义 view 如何接收请求和处理原始数据，而不是字段定义的 model 和 serializer .

我给你一个基本 User 操作的CRUD示例作为参考：

lu = LibraryUser（library_membership_number ='...'，user_id = user）

class ExampleAPIView(APIView):
    def get(self, request):
        username = request.query_params.get('username', '')
        user = User.objects.get(username=username)
        return Response(ExampleSerializer(user).data)

    def post(self, request):
        username = request.data.get('username', '')
        email = request.data.get('email', '')
        password = request.data.get('password', '')
        user = User.objects.create_user(username=username, email=email, password=password)
        user.save()
        Response({'status': 'ok'}})

    def put(self, request):
        username = request.data.get('username', '')
        old_password = request.data.get('old_password', '')
        new_password = request.data.get('new_password', '')
        user = authenticate(username=username, password=old_password)
        if not user:
            return Response({'status': 'fail'}})
        user.set_password(new_password)
        return Response({'status': 'ok'}})

    def delete(self, request):
        username = request.query_params.get('username', '')
        user.objects.get(username=username).delete()
        return Response({'status': 'ok'}})

根据示例，这些是我对每种方法的定义：

GET ：检索用户 Profiles
POST ：创建新用户
PUT ：更改密码的用户
DELETE ：删除用户

因此，它将为 user 实例实现Basic CRUD api .

我希望它可以帮助你如何设计api .

如果您还不了解如何操作 model ，我将更多介绍该示例：

class ExampleAPIView(APIView):
    def get(self, request):
        username = request.query_params.get('username', '')
        userprofile = UserProfile.objects.get(user__username=username)
        return Response(ExampleSerializer(userprofile).data)

    def put(self, request):
        username = request.data.get('username', '')
        userprofile = UserProfile.objects.get(user__username=username)
        if not userprofile :
            return Response({'status': 'fail'}})
        userprofile.location = ...
        userprofile.title = ...
        userprofile.website = ...
        userprofile.save()
        return Response({'status': 'ok'}})

回复于 2024-05-04T12:34:01+08:00

Django REST：为OneToOne Field创建CRUD操作

2 回答

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