在iPhone App中如何检测设备的屏幕分辨率

6 回答

• 5

  CGRect screenBounds = [[UIScreen mainScreen] bounds];
  

  这将为您提供整个屏幕的分辨率，因此iPhone最常用的是320x480 . 尽管iPhone4的屏幕尺寸要大得多，但iOS仍然可以提供320x480而不是640x960 . 这主要是因为较旧的应用程序崩溃 .

  CGFloat screenScale = [[UIScreen mainScreen] scale];
  

  这将为您提供屏幕的比例 . 对于没有Retina显示器的所有设备，这将返回1.0f，而Retina显示设备将提供2.0f，而iPhone 6 Plus（Retina HD）将提供3.0f .

  现在，如果您想获得iOS设备屏幕的像素宽度和高度，您只需要做一件简单的事情 .

  CGSize screenSize = CGSizeMake(screenBounds.size.width * screenScale, screenBounds.size.height * screenScale);
  

  通过乘以屏幕的比例，您可以获得实际的像素分辨率 .

  有关iOS中像素和像素之间差异的详细信息，请阅读here .

  EDIT: （Swift版本）

  let screenBounds = UIScreen.main.bounds
  let screenScale = UIScreen.main.scale
  let screenSize = CGSize(width: screenBounds.size.width * screenScale, height: screenBounds.size.height * screenScale)
  

  回复于 2024-04-29T06:25:35+08:00
• 339

  UIScreen类允许您以点和像素查找屏幕分辨率 .

  屏幕分辨率以点或像素为单位 . 它绝不应与屏幕尺寸混淆 . 较小的屏幕尺寸可以具有更高的分辨率 .

  UIScreen 's ' bounds.width'返回点的矩形大小
  

  UIScreen 's ' nativeBounds.width'以像素为单位返回矩形大小 . 此值被检测为PPI（每英寸点数） . 显示设备上图像的清晰度和清晰度 .
  

  您可以使用UIScreen类来检测所有这些值 .

  Swift3

  // Normal Screen Bounds - Detect Screen size in Points.
  let width = UIScreen.main.bounds.width
  let height = UIScreen.main.bounds.height
  print("\n width:\(width) \n height:\(height)")
  
  // Native Bounds - Detect Screen size in Pixels.
  let nWidth = UIScreen.main.nativeBounds.width
  let nHeight = UIScreen.main.nativeBounds.height
  print("\n Native Width:\(nWidth) \n Native Height:\(nHeight)")
  

  Console

  width:736.0 
  height:414.0
  
  Native Width:1080.0 
  Native Height:1920.0
  

  Swift 2.x

  //Normal Bounds - Detect Screen size in Points.
      let width  = UIScreen.mainScreen.bounds.width
      let height = UIScreen.mainScreen.bounds.height
  
  // Native Bounds - Detect Screen size in Pixels.
      let nWidth  = UIScreen.mainScreen.nativeBounds.width
      let nHeight = UIScreen.mainScreen.nativeBounds.height
  

  ObjectiveC

  // Normal Bounds - Detect Screen size in Points.
  CGFloat *width  = [UIScreen mainScreen].bounds.size.width;
  CGFloat *height = [UIScreen mainScreen].bounds.size.height;
  
  // Native Bounds - Detect Screen size in Pixels.
  CGFloat *width  = [UIScreen mainScreen].nativeBounds.size.width
  CGFloat *height = [UIScreen mainScreen].nativeBounds.size.width
  

  回复于 2024-04-29T06:25:35+08:00
• 13

  在App Delegate中使用它：我正在使用故事板

  - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions{
  
  if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
  
      CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
  
      //----------------HERE WE SETUP FOR IPHONE 4/4s/iPod----------------------
  
      if(iOSDeviceScreenSize.height == 480){          
  
          UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"iPhone" bundle:nil];
  
          // Instantiate the initial view controller object from the storyboard
          UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController];
  
          // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
          self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
  
          // Set the initial view controller to be the root view controller of the window object
          self.window.rootViewController  = initialViewController;
  
          // Set the window object to be the key window and show it
          [self.window makeKeyAndVisible];
  
          iphone=@"4";
  
          NSLog(@"iPhone 4: %f", iOSDeviceScreenSize.height);
  
      }
  
      //----------------HERE WE SETUP FOR IPHONE 5----------------------
  
      if(iOSDeviceScreenSize.height == 568){
  
          // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
          UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"iPhone5" bundle:nil];
  
          // Instantiate the initial view controller object from the storyboard
          UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController];
  
          // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
          self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
  
          // Set the initial view controller to be the root view controller of the window object
          self.window.rootViewController  = initialViewController;
  
          // Set the window object to be the key window and show it
          [self.window makeKeyAndVisible];
  
           NSLog(@"iPhone 5: %f", iOSDeviceScreenSize.height);
          iphone=@"5";
      }
  
  } else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
      // NSLog(@"wqweqe");
      storyboard = [UIStoryboard storyboardWithName:@"iPad" bundle:nil];
  
  }
  
   return YES;
   }
  

  回复于 2024-04-29T06:25:35+08:00
• 8

  对于iOS 8，我们可以使用这个 [UIScreen mainScreen].nativeBounds ，就像这样：

  - (NSInteger)resolutionX
  {
      return CGRectGetWidth([UIScreen mainScreen].nativeBounds);
  }
  
  - (NSInteger)resolutionY
  {
      return CGRectGetHeight([UIScreen mainScreen].nativeBounds);
  }
  

  回复于 2024-04-29T06:25:35+08:00
• 0

  请参阅UIScreen参考：http://developer.apple.com/library/ios/#documentation/uikit/reference/UIScreen_Class/Reference/UIScreen.html

  if([[UIScreen mainScreen] respondsToSelector:NSSelectorFromString(@"scale")])
  {
      if ([[UIScreen mainScreen] scale] < 1.1)
          NSLog(@"Standard Resolution Device");
  
      if ([[UIScreen mainScreen] scale] > 1.9)
          NSLog(@"High Resolution Device");
  }
  

  回复于 2024-04-29T06:25:35+08:00
• 4

  使用此代码可以帮助您获取任何类型的设备屏幕分辨率

  [[UIScreen mainScreen] bounds].size.height
   [[UIScreen mainScreen] bounds].size.width
  

  回复于 2024-04-29T06:25:35+08:00