我最近在Codecademy上学习了Python，所以我决定为我的第一个真正的程序做一个摇滚，纸张，剪刀游戏，因为它看起来很简单 .
在测试程序时，Python似乎忽略了嵌套在while循环中的大if / elif语句 . 游戏生成一个随机整数（0为摇滚，1为纸，2为剪刀），然后打印（用于调试） . 然后它会提示玩家输入 . 之后，不是用if语句评估选择，而是要求玩家做出另一种选择 . 它还打印一个新的随机整数，所以我知道它只是跳过if语句并返回到while循环的开头 .
以下是游戏的代码 . 如果if语句出现某种语法错误，我就没有看到它 . 有谁知道发生了什么？
from random import randint
def choose():
print '\nWill you play rock, paper, or scissors?'
rawhumanchoice = raw_input('> ')
if rawhumanchoice == 'rock' or rawhumanchoice == 'r':
humanchoice = 0
elif rawhumanchoice == 'paper' or rawhumanchoice == 'p':
humanchoice = 1
elif rawhumanchoice == 'scissors' or rawhumanchoice == 's':
humanchoice = 2
else:
print '\nSorry, I didn\'t catch that.'
choose()
def gameinit():
roundsleft = 0
pcwins = 0
humanwins = 0
print 'How many rounds do you want to play?'
roundsleft = raw_input('> ')
while roundsleft > 0:
pcchoice = randint(0,2)
print pcchoice
humanchoice = -1
choose()
if humanchoice == 0: #This is what Python ignores
if pcchoice == 0:
print '\nRock and rock... it\'s a tie!'
roundsleft -= 1
elif pcchoice == 1:
print '\nPaper beats rock... PC wins.'
roundsleft -= 1
pcwins += 1
elif pcchoice == 2:
print '\nRock beats scissors... human wins!'
roundsleft -= 1
humanwins += 1
elif humanchoice == 1:
if pcchoice == 0:
print '\nPaper beats rock... human wins!'
roundsleft -= 1
humanwins += 1
elif pcchoice == 1:
print '\nPaper and paper... it\'s a tie!'
roundsleft -= 1
elif pcchoice == 2:
print '\nScissors beat paper... PC wins.'
roundsleft -= 1
pcwins += 1
elif humanchoice == 2:
if pcchoice == 0:
print '\nRock beats scissors... PC wins.'
roundsleft -= 1
pcwins += 1
elif pcchoice == 1:
print '\nPaper beats rock... human wins!'
roundsleft -= 1
humanwins += 1
elif pcchoice == 2:
print '\nScissors and scissors... it\'s a tie!'
roundsleft -= 1
else:
if humanwins > pcwins:
result = 'The human wins the match!'
elif humanwins < pcwins:
result = 'The PC wins the match.'
elif humanwins == pcwins:
result = 'The match is a tie!'
print '\nThe score is %s:%s... %s \n' % (humanwins,pcwins,result)
gameinit()
gameinit()
2 回答
choose()不返回值 . 因此它总是返回None.None永远不会等于0. 因此，永远不会触发if语句 .在Python 3中，比较
None和0实际上是一个错误，这将有助于您更快地解决这个问题 . 但是，即使在Python 2中，在您调用choose()之后，一个简陋的print humanchoice语句很快就会显示您从函数中得到的除了None之外没有任何东西 .在
choose()末尾添加return humanchoice.你缺少从方法选择返回，并 grab 它