我正在尝试使用libgdx绘制bezier曲线 .

Vector2 pixel0 = Line.CalculateBezierPoint(0, p0, p1, p2, p3);
    System.out.print(pixel0.x);
    for(int i = 1; i <= 10; i++)
    {
        System.out.print(pixel0.x);
        float t = i / (float) 10;
        Vector2 pixel1 = Line.CalculateBezierPoint(t, p0, p1, p2, p3); //after this line pixel0 equals pixel1, why?
        //batch.draw(rect, pixel.y, pixel.x, 3, 3);
        //shapeRenderer = new ShapeRenderer();
        Gdx.gl20.glLineWidth(2);
        shapeRenderer.setProjectionMatrix(camera.combined);
        shapeRenderer.begin(ShapeType.Line);
        shapeRenderer.setColor(255,255,255,255);
        shapeRenderer.line(pixel0, pixel1);

        shapeRenderer.end();
        pixel0 = pixel1;

    }

public class Line {
    public static Vector2 CalculateBezierPoint(float t, Vector2 p0, Vector2 p1, Vector2 p2, Vector2 p3) {
        float u = 1 - t;
        float tt = t*t;
        float uu = u*u;
        float uuu = uu * u;
        float ttt = tt * t;

        Vector2 p = p0.scl(uuu);
        p.add(p1.scl(3 * uu * t));
        p.add(p2.scl(3 * u * tt));
        p.add(p3.scl(ttt));

        return p;
    }
}

如果pixel0 = pixel1存在或不存在则无关紧要 . 每次pixel0都是由pixel1写的，但是怎么样，为什么呢？

编辑;工作代码：

Vector2 pixel0 = new Vector2(Line.CalculateBezierPoint(0, p0, p1, p2, p3));
    for(int i = 1; i <= 2; i++)
    {
        float t = i / (float) 2;
        Vector2 pixel1 = new Vector2(Line.CalculateBezierPoint(t, p0, p1, p2, p3));
        //batch.draw(rect, pixel.y, pixel.x, 3, 3);
        //shapeRenderer = new ShapeRenderer();
        Gdx.gl20.glLineWidth(2);
        shapeRenderer.setProjectionMatrix(camera.combined);
        shapeRenderer.begin(ShapeType.Line);
        shapeRenderer.setColor(255,255,255,255);
        shapeRenderer.line(pixel0, pixel1);

        shapeRenderer.end();
        pixel0 = pixel1;

    }

CalculateBezierPoint是一个静态函数，我试图每次都去除deklare新函数，并且它绘制简单的线条，而不是曲线 . 我用过：http://devmag.org.za/2011/04/05/bzier-curves-a-tutorial/并将CalculateBezierPoint函数转换为Java . 有人检查，如果我做得好吗？

java libgdx